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jeka94
4 years ago
5

450 mistakes in 9 test

Mathematics
2 answers:
IrinaVladis [17]4 years ago
6 0
no context but 50 mistakes averaged every test
Tatiana [17]4 years ago
3 0
50 mistakes on average per test if that what your looking for
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Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree
VladimirAG [237]
The problem above uses a combination of sine and cosine law of triangle to solve for the m∠B. 

Given:
<span>m∠A = 60°, b = 9 and c = 6

Cosine Law:
a^2=b^2+c^2-2bccosA
a^2=(9)^2+(6)^2-2(9)(6)cos(60)
a^2=81+36-54
a^2= 63
a=</span>\sqrt{63}

Sine Law
\frac{sin(A)}{a} = \frac{sin (B)}{9}
sin B= 9/ \sqrt{63} sin 60
sin B= 0.98198
B= sin ^-1 (0.98198) = 79.10

Therefore, m∠B is equal to 79.10
7 0
3 years ago
900 x 20.9 need now plz
erica [24]
The answer to your question is 18810
5 0
3 years ago
Read 2 more answers
The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen
vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.75

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897

P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339

P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669

P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211

P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.75 = 16.5

The closest integer to 16.5 is 17.

7 0
3 years ago
Factor - 3y(2y + 3) - 5(2y + 3)
avanturin [10]

Answer:

-(2y+3)×(3y+5)

Step-by-step explanation:

- 3y(2y + 3) - 5(2y + 3)

Factor out - (2y+3)

-(2y+3)×(3y+5)

4 0
4 years ago
I will give Brainiest if you are right
ira [324]
The answer is H. 2x>12
8 0
3 years ago
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