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11111nata11111 [884]
3 years ago
7

I need help with this question

Mathematics
2 answers:
leonid [27]3 years ago
8 0
The answer must be G, after calculating, I got 5.45
Rama09 [41]3 years ago
6 0

Answer:

G

Step-by-step explanation:

An integer is a whole number. Round each of your answers to the nearest tenth (for the 5's, you round up), and you see that choice G, 5.5, can be divided by 1.1 to equal 5.

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Which value is the 10th term in the sequence:-62,-47,-32,-17,-2?
balu736 [363]
The answer is 13
Sure!!!
5 0
3 years ago
A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha
8_murik_8 [283]
To model this situation, we are going to use the decay formula: A=Pe^{rt}
where 
A is the final pupolation
P is the initial population 
e is the Euler's constant
r is the decay rate 
t is the time in years

A. We know for our problem that the initial population is 1,250, so P=1250; we also know that after a year the population is 1000, so A=1000 and t=1. Lets replace those values in our formula to find r:
A=Pe^{rt}
1000=1250e^{r}
e^{r}= \frac{1000}{1250}
e^{r}= \frac{4}{5}
ln(e^{r})=ln( \frac{4}{5} )
r=ln( \frac{4}{5} )
r=-02231

Now that we have r, we can write a function to model this scenario:
A(t)=1250e^{-0.2231t}.

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C. 
- The function is decreasing
- The function doe snot have a x-intercept 
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0: 
A(0)=1250e^{(-0.2231)(0)
A_{0}=1250e^{0}
A_{0}=1250
- Over the interval [0,10], the function will have a minimum at t=10:
A(10)=1250e^{(-0.2231)(10)
A_{10}=134.28

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: m= \frac{A(0)-A(10)}{10-0}
where 
m is the rate of change 
A(10) is the function evaluated at 10
A(0) is the function evaluated at 0
We know from previous calculations that A(10)=134.28 and A(0)=1250, so lets replace those values in our formula to find m:
m= \frac{134.28-1250}{10-0}
m= \frac{-1115.72}{10}
m=-111.572
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0
3 years ago
numerele a, b si c sunt direct proportionale cu 2, 3 si 5. Daca media aritmetica a celor trei numere este egala cu 100, determin
Fynjy0 [20]

Answer:

a = 60

b = 90

c = 150

Step-by-step explanation:

Numerele a, b și c sunt direct proporționale cu 2, 3 și 5.

Unde k este constantă de proporționalitate

a ∝ 2

a = 2k

b ∝ 3

b = 3k

c ∝ 5

c = 5k

Dacă media aritmetică a celor trei numere este egală cu 100, determinați numerele a, b și c

= 2k + 3k + 5k / 3 = 100

= 10k / 3 = 100

Cross Multiply

= 10k = 3 × 100

= 10k = 300

Împărțiți ambele părți la 10

k = 300/10

k = 30

Pentru numărul a

a = 2k

a = 2 × 30

a = 60

Pentru numărul b

b = 3k

b = 3 × 30

b = 90

Pentru numărul c

c = 5k

c = 5 × 30

c = 150

Prin urmare, a = 60, b = 90, c = 150

3 0
3 years ago
In the inequality 6a+4b>10, what could be the possible value of a if b=2?
Arlecino [84]

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

\frac{6a}{6}>\frac{2}{6}

Simplifying:

a>\frac{1}{3}

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0
1 year ago
Tşk şimdiden <br><br><br><br><br><br><br> 17 puan
Kamila [148]

Answer:

um what-?

Step-by-step explanation:

5 0
3 years ago
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