Answer:
-63
Step-by-step explanation:
Answer:
v = 8.49 m/s rounded off to 3 significant figures
Step-by-step explanation
Using Energy Conservation
U = Tk + Vp (Sum of kinetic Tk Energy and gravitational potential Vp Energy)
- At height = 3.67 m, the hammer was still or the velocity was negligible; hence, vi = 0 m/s.
- Ui = 0 + mgh
- At ground all potential energy is converted to kinetic; hence, Uf =
mv². - Since total energy of the system remains constant we equate Ui to Uf.
- Ui = Uf
- mgh =
mv² - After cancelling out masses and making v the subject of the formula we get:
v =
=
= 8.49 m/s rounded off to 3 significant figures
Well, first you have to simplify the equation,
y + 7 = 12(x - 5)
y + 7 = 12x - 60
-7 -7
y = 12x - 67
Then graph!
(6p-1)(6p+1)
Step-by-step explanation:
Now foil. You would get 36p^2+6p-6p-1 so you cancel out your 6ps and that leaves you with (6p-1)(6p+1)