Answer:
The plane's distance from the radar station will increase about 8 miles per minute when it is 5 miles away from it.
Step-by-step explanation:
When the plane passes over the radar station, the current distance is the altitude h = 2. Then it moves b horizontally so that the distance to the station is 5. We can form a rectangle triangle using b, h and the hypotenuse 5. Therefore, b should satisfy
h²+b² = 5², since h = 2, h² = 4, as a result
b² = 25-4 = 21, thus
b = √21.
Since it moved √21 mi, then the time passed is √21/540 = 0.008466 hours, which is 0.51 minutes. Note that in 1 minute, the plane makes 540/60 = 9 miles.
The distance between the plane and the radar station after x minutes from the moment that the plane passes over it is given by the function
We have to compute the derivate of f in x = 0.51. The derivate of f is given by
also,
The plane's distance from the station will increase about 8 miles per minute.
The three points give you three equations, which you can solve by your favorite method.
.. 0m +0n +b = 6
.. 1m +0n +b = -3
.. 0m +2n +b = 5
(m, n, b) = (-9, -1/2, 6)
so the equation of the plane can be written as
.. z = -9x -1/2y +6
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In standard form, this would be
.. 18x +y +2z = 12
C. Is the answer to this question
Answer:
not a function; (2, -2) and (2, 2)
Step-by-step explanation:
A vertical line has the same x-value for all of its y-values. Only the last answer choice lists two points on a vertical line. They also happen to be points on the graph, so it is NOT a function.
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Any vertical line in the x-interval (-3, 3) will pass through the segments y=-2 and y=2. Vertical lines at x=-3 or x=3 will pass through an infinite number of points between y=-2 and y=2.
Answer:
Value of f (Parapedicular) = 7√6
Step-by-step explanation:
Given:
Given triangle is a right angle triangle
Value of base = 7√2
Angle made by base and hypotenuse = 60°
Find:
Value of f (Parapedicular)
Computation:
Using trigonometry application
Tanθ = Parapedicular / Base
Tan60 = Parapedicular / 7√2
√3 = Parapedicular / 7√2
Value of f (Parapedicular) = 7√2 x √3
Value of f (Parapedicular) = 7√6
