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UNO [17]
3 years ago
6

A line is defined by the equation y=2/3x-6. The line passes through a point whose y-coordinate is 0. What is the x-coordinate of

this point?
Mathematics
2 answers:
lianna [129]3 years ago
7 0

Answer:

x=9

Step-by-step explanation:

Use the equation of the line and let y=0. Then solve for x.

y=2/3x-6

Let y=0:

0=2/3x-6

Add six to both sides.

6=2/3x

Multiply both sides by 3/2.

3/2*6=x

x=9

adelina 88 [10]3 years ago
6 0
Y = (2/3).x - 6. If y=0, then 0= (2/3).x - 6. Solve for x:

2x/3 - 6 = 0
Same denominator:
(2x - 18)/3 = 0
2x - 18 = 0
2x = 18 and x = 9 (x-coordinate)
 

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3 years ago
I need to find the perimeter and area of the regular polygon.
mezya [45]
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Depending on the formula you know, you can find the length of a side in 1 of 2 ways. 

The first way uses a triangle. Using the radius of the polygon you can create 8 congruent triangles. The center angle will be 360 / 8 = 45 and two side lengths of 20. You can find the length of the base using the law of cosines.

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c^2 = 800 - 800(cos 45)
c = sqrt(800 - 800(cos 45)
c = 15.31

The second way is to use this formula:
r = s / (2 sin(180 / n))
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(40)sin(22.5) = s
s = 15.31

We need to calculate the perimeter. As there are 8 sides (8)(15.31) = 122.48
Now we need to calculate the apothem using

a = S / (2 tan (180 / n)
a = 15.31 / (2 tan (180 / 8))
a = 18.48

Now solve for the area

Area = ap/2
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Area = 1131.72

perimeter = 122.48
area = 1131.72
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