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UNO [17]
3 years ago
6

A line is defined by the equation y=2/3x-6. The line passes through a point whose y-coordinate is 0. What is the x-coordinate of

this point?
Mathematics
2 answers:
lianna [129]3 years ago
7 0

Answer:

x=9

Step-by-step explanation:

Use the equation of the line and let y=0. Then solve for x.

y=2/3x-6

Let y=0:

0=2/3x-6

Add six to both sides.

6=2/3x

Multiply both sides by 3/2.

3/2*6=x

x=9

adelina 88 [10]3 years ago
6 0
Y = (2/3).x - 6. If y=0, then 0= (2/3).x - 6. Solve for x:

2x/3 - 6 = 0
Same denominator:
(2x - 18)/3 = 0
2x - 18 = 0
2x = 18 and x = 9 (x-coordinate)
 

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What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36
GREYUIT [131]
ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

f(x) = {x}^{4} - 13 {x}^{2} + 36

To find the real roots, we equate the function to zero to obtain;

{x}^{4} - 13 {x}^{2} + 36 = 0

We can solve this equation as a quadratic equation in
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Thus we rewrite the equation as,

({x}^{2})^{2} - 13 {x}^{2} + 36 = 0

We split the middle term to get,

({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.

We factor to get,

{x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0

We factor to get,

( {x}^{2} - 9)( {x}^{2} - 4) = 0

Either

{x}^{2} - 9 = 0
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{x}^{2} - 4 = 0

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The correct answer is A
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