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UNO [17]
3 years ago
6

A line is defined by the equation y=2/3x-6. The line passes through a point whose y-coordinate is 0. What is the x-coordinate of

this point?
Mathematics
2 answers:
lianna [129]3 years ago
7 0

Answer:

x=9

Step-by-step explanation:

Use the equation of the line and let y=0. Then solve for x.

y=2/3x-6

Let y=0:

0=2/3x-6

Add six to both sides.

6=2/3x

Multiply both sides by 3/2.

3/2*6=x

x=9

adelina 88 [10]3 years ago
6 0
Y = (2/3).x - 6. If y=0, then 0= (2/3).x - 6. Solve for x:

2x/3 - 6 = 0
Same denominator:
(2x - 18)/3 = 0
2x - 18 = 0
2x = 18 and x = 9 (x-coordinate)
 

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What is the incorrect rounding for 53.864
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How do you write 996 as a fraction, mixed number, or whole number in simplest form?
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5 0
3 years ago
Read 2 more answers
Let F(X) = x^2-16x+71. What is the vertex and minimum value of F(X)?
LekaFEV [45]
The veretx is normally the minimum value
hack:
for f(x)=ax²+bx+c
the x value of the vertex is -b/2a
so
f(x)=1x²-16x+71
x value is -(-16)/(2*1)=16/2=8
find f(8) to find y value of vertex

f(8)=8²-16(8)+71
f(8)=64-128+71
f(8)=7


the vertex is (8,7)
the minimum value is 7
7 0
3 years ago
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