Question

What the center of X^2+(y+3)=9

Answer 1

Assuming you mean $x^2+(y+3)^2=9$, which is the equation of a circle :

the general equation of a circle of radius $R$ and center $(a,b)$ is $(x-a)^2+(y-b)^2=R^2$ hence here the center is $\boxed{(0,-3)}$