Question

What are the vertex and axis of symmetry of the parabola y = x2 – 16x + 63?

Answer 1

Answer:

A

Step-by-step explanation:

Remember that the x-value of the vertex when an equation is given in standard form can be found with the equation $\frac{-b}{2a}$. So, we can take the coefficients from the equation and plug them in.

$\frac{-b}{2a} \\\frac{-(-16)}{2(1)}\\\\\frac{16}{2}\\\\8$

Now we know that the x-value of the vertex is 8. Next, the equation for the y-value is $c-ah^2$, where h is the x-value of the vertex (8).

$(63)-(1)(8)^2\\63-64\\-1$

So the vertex is (8,-1).

Finally, the axis of symmetry is the x-value of the vertex, also called h.

Final answer, vertex: (8,-1) and axis of symmetry: x=8

Hope this helps!