3 years ago

What is the area of the irregular pentagon

Mathematics

2 answers:

V125BC [204]3 years ago

8 0

Answer:

Answer is 105 in^2

Step-by-step explanation: Area of rectangle= length X breadth

= 8X12

=96in^ 2

Area of triangle= 1/2 X base X height

= 1/2 X 3 X 6

= 9 in^2

Area of irregular pentagon = area of triangle + area of rectangle

= 96+9

=105 in ^2

Ket [755]3 years ago

5 0

Answer:

Answer is 105 in^2

Step-by-step explanation:

Area of rectangle= length X breadth = 8X12=96in^ 2Area of triangle= 1/2 X base X height= 1/2 X 3 X 6= 9 in^2 Area of irregular pentagon = area of triangle + area of rectangle = 96+9=105 in ^2

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4 years ago

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elena55 [62]

Answer:

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Step-by-step explanation:

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4 years ago

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