All categories

3 years ago

Please help im so bad at math

Mathematics

1 answer:

Vlad1618 [11]3 years ago

7 0

Just the 1 (corresponding to the tallest bar between 45.0 and 52.5 on the horizontal axis)

You might be interested in

A recipe calls for 3 cups of sugar and 9 cups of water. How many should be used with 2 cups of sugar?

9966 [12]

Answer:

6 cups of water

Step-by-step explanation:

A recipe calls for 3 cups of sugar and 9 cups of water. How many should be used with 2 cups of sugar?

The question above, is solved below:

3 cups of sugar = 9 cups of water

2 cups of sugar = x

Cross Multiply

3x = 9 × 2

x = 18/3

x = 6

Hence, 2 cups of sugar = 6 cups of water

8 0

3 years ago

How are dot products useful?

nata0808 [166]

Answer:

An important use of the dot product is to test whether or not two vectors are orthogonal. Two vectors are orthogonal if the angle between them is 90 degrees. ... Thus, two non-zero vectors have dot product zero if and only if they are orthogonal.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How would you graph and solve this ?? Plz help! Open to see image.

Archy [21]

Check the picture below.

keep in mind that an absolute value expression is in effect a piece-wise.

$\bf |x-4|\le 2\implies 
\begin{cases}
+(x-4)\le 2\\
-------\\
-(x-4)\le 2\\
x-4\ge -2
\end{cases}\implies 
\begin{array}{llll}
-2\le x-4\le 2\\\\
\textit{adding 4 to all 3 sides}\\\\
\boxed{2\le x \le 6}
\end{array}\\\\
-------------------------------\\\\
|x-5|\ \textgreater \ 3\implies 
\begin{cases}
+(x-5)\ \textgreater \ 3\\
-------\\
-(x-5)\ \textgreater \ 3\\
x-5\ \textless \ -3
\end{cases}\implies 
\begin{array}{llll}
3\ \textless \ x-5\ \textless \ -3\\\\
\textit{adding 5 to all 3 sides}\\\\
\boxed{8\ \textless \ x\ \textless \ 2}
\end{array}$

4 0

3 years ago

for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a ju

Igoryamba

Answer:

ITS UNDEFINED

Step-by-step explanation:

2-3)/2^2 - 4

-1/(4-4)

-1/0

ITS UNDEFINED

3 0

3 years ago

Read 2 more answers

one x-intercept for a parabola is at the point (3.22,0) find the other x-intercept for the parabola defined by this equation y=2

Paul [167]

Answer:

(0.78,0)

Step-by-step explanation:

I would use the quadratic formula.

$a=3$

$b=-8$

$c=5$

$\text{ The quadratic formula is } x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{ Let's find } b^2-4ac \text{ first}\\(-8)^2-4(2)(5)\\64-8(5)\\64-40\\24\\\\\text{ Now let's find } -b\\-b=8\\\text{ And } 2a\\2(2)=4\\\\\text{ Let's plug in this information }\\x=\frac{8 \pm \sqrt{24}}{4}\\\\\text{ We are now going to simplify }\\x=\frac{8}{4} \pm \frac{\sqrt{24}}{4} \\x=2 \pm \frac{\sqrt{4 \cdot 6}}{4}\\x=2 \pm \frac{\sqrt{4} \sqrt{6}}{4} \\x=2 \pm \frac{2 \sqrt{6}}{4}\\$

$x=2 \pm \frac{\sqrt{6}}{2}$

So let's put both of these into out calculator

2 + sqrt(6)/2 and 2-sqrt(6)/2

One of them should be approximately 3.22 as the question suggests.

3.22 0.78

So the other x-intercept is approximately (0.78,0)

3 0

3 years ago