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4 years ago

X+4 x+1

Mathematics

1 answer:

tiny-mole [99]4 years ago

4 0

Answer:

5x i think

Step-by-step explanation:

hopenit is right

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Lim ln(tan x) as tends to pi/2 from the left

ioda

Let $x=\arctan y$ . Then $\tan x=y$ , and so as $x\to\dfrac\pi2^-$ , you have $y\to+\infty$ . The limit is then equivalent to

$\displaystyle\lim_{x\to\frac\pi2^-}\ln(\tan x)=\lim_{y\to\infty}\ln y=\infty$

3 0

3 years ago

Need help, have to submit this very soon!!

Brut [27]

Answer:

see explanation

Step-by-step explanation:

length = $\frac{60}{8}$ = 7.5 in

scale factor = $\frac{image}{original}$ = $\frac{8}{60}$ = $\frac{2}{15}$

---------------------------------------------------

length = $\frac{192}{4}$ = 48 cm

scale factor = $\frac{omage}{original}$ = $\frac{4}{192}$ = $\frac{1}{48}$

5 0

3 years ago

(2x/3)-(5x/9)-(x/6)-(5x/12)=13/2 this equation is equivalent to:

agasfer [191]

Answer:

-17x=234

Step-by-step explanation:

Given that:

$\dfrac{2x}{3}-\dfrac{5x}{9}-\dfrac{x}{6}-\dfrac{5x}{12}=\dfrac{13}{2}$

$\dfrac{72x-60x -18x-45x }{108} = \dfrac{13}{2}$

$\dfrac{-51x }{108} = \dfrac{13}{2}$

$-102x = 1404$

$-\dfrac{102x}{6} = \dfrac{1404}{6}$

-17x = 234

6 0

3 years ago

Consider the following system:

Goryan [66]

You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers.

<span>A multiple of Equation 1.
B. The sum of Equation 1 and Equation 2
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2.
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2.
E. The sum of a multiple of Equation 1 and Equation 2.

</span>A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.

4 0

3 years ago

Read 2 more answers

HELP ASAP

Naily [24]

Answer:

$y+4 = -\frac{1}{3} (x-1)$

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ to find the slope. Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(-5)-(-4)}{(4)-(1)} \\m = \frac{-5+4}{4-1} \\m = \frac{-1}{3}$

So, the slope is $-\frac{1}{3}$ .

2) Use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line in point-slope form. Substitute values for $m$ , $x_1$ , and $y_1$ into the formula.

Since $m$ represents the slope, substitute $-\frac{1}{3}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of one point on the line, choose any one of the given points (it doesn't matter which one) and substitute the x and y values of it into the formula. (I chose (1,-4), as seen below). This gives the equation of the line in point-slope form.

$y-(-4) = -\frac{1}{3} (x-(1))\\y+4 = -\frac{1}{3} (x-1)$

5 0

2 years ago

Read 2 more answers