All categories

2 years ago

A number when added to it's two thirds is equal to 55 find the number

Mathematics

1 answer:

tatyana61 [14]2 years ago

8 0

Answer:

<h2>Let the number is = X </h2><h2>Two thirds of the number = 2x/3</h2><h2 /><h2>According to the problem given,</h2><h2>x+ 2x/3 = 55</h2><h2>( 3x + 2x ) /3 = 55</h2><h2>5x /3 = 55</h2><h2>x = ( 55 × 3 ) /5</h2><h2>x = 11 × 3</h2><h2>x = 33 </h2>

<h2>Therefore,</h2><h2>Required number = x = 33</h2>

You might be interested in

Simplify the expression √39(√6+7)

IrinaVladis [17]

The answer that I got is 3 $\sqrt{26} + \sqrt{273}$

3 0

4 years ago

Which expression is equivalent to<br> 128x8,329 ? Assume y20 and 720

kaheart [24]

Answer:767600640

Step-by-step explanation: If 720 equals x, you multiply 128 by 720, and multiply the answer by 8,329.

8 0

3 years ago

A phone company offers two packages of service. Package A is $35.00 per month with an additional charge of $0.15 per minute for

ella [17]

Answer: 200 minutes have to be used for the costs of both plans to be the same.

Step-by-step explanation:

Let x represent the number of minutes that have to be used for the costs of both plans to be the same.

Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. This means that the cost of using package A for x minutes in a month would be

35 + 0.15x

Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. This means that the cost of using package A for x minutes in a month would be

45 + 0.1x

For both costs to be the same, it means that

35 + 0.15x = 45 + 0.1x

0.15x - 0.1x = 45 - 35

0.05x = 10

x = 10/0.05

x = 200

3 0

3 years ago

) Solve the inequality n -7> -4.<br><br><br><br> HELP ASAP DUE IN A COUPLE HOURS

PilotLPTM [1.2K]

Answer:

n>3

Step-by-step explanation:

HOPE THIS HELPED IF YOU WANT I CAN HELP YOU IF THERES ANYMORE.

6 0

3 years ago

Prove that C(50,3) + C(50,4) = C(51,4)

valkas [14]

By definition of the binomial coefficient,

$C(n,k) = \dfrac{n!}{k!(n-k)!}$

so we have

$C(50,3) + C(50,4) = \dfrac{50!}{3!47!} + \dfrac{50!}{4!46!} \\\\ = \dfrac{50!}{3!46!} \left(\dfrac1{47} + \dfrac14\right) \\\\ = \dfrac{50!}{3!46!} \times \dfrac{51}{188} \\\\ = \dfrac{51!}{3!46!} \times \dfrac1{4\times47} \\\\ = \dfrac{51!}{4!47!} \\\\ = \dfrac{51!}{4!(51-4)!} = C(51,4)$

as required.

5 0

2 years ago