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3 years ago

PLEASE ANSWER ASAP! NO EXPLANATION NEEDED!

Mathematics

2 answers:

adell [148]3 years ago

5 0

Answer:

3/5

Step-by-step explanation:

you said I didn't need an explanation

BigorU [14]3 years ago

3 0

Answer:

Simplified Solution = 3 / 5

Step-by-step explanation:

Take a look at the procedure below;

$- ( - 7 / 10 - 3 / 5 ) - ( 1 / 6 + 2 / 3 ) - ( - 2 / 15 ),\\7 / 10 + 3 / 5 - 1 / 6 - 2 / 3 + 2 / 15,\\7 / 10 + 6 / 10 - 1 / 6 - 4 / 6 + 2 / 15,\\\\13 / 10 - 5 / 6 + 2 / 15\\39 / 30 - 25 / 30 + 4 / 30\\18 / 20\\3 / 5 \\\\Conclusion, 3 / 5$

For the first step we applied the distributive property, simplify the expression. Taking the LCM of fractions, we derived similar fractions of like denominators. Adding / Subtracting, we got a further simplified solution ⇒ 3 / 5

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Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

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Answer:

Step-by-step explanation:

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2 years ago

Use substitution method 3x +4y+175x-2y=11

Viefleur [7K]

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$4y-2y+175x+3x=11$

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$y=\frac{11-178x}{2}$

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$178x=-2y+11$

$x=\frac{-2y+11}{178}$

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2 years ago

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Can you add the picture?

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3 years ago

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3 years ago