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antoniya [11.8K]
4 years ago
8

Please help me. It’s urgent.

Mathematics
1 answer:
sergeinik [125]4 years ago
5 0
The answer to the question

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Which term best describes the set of all points in a plane for which the sum
alina1380 [7]
The answer is gonna be Parabola for sure
5 0
3 years ago
Use the explicit formula an=a1+(n-1)•d to find the 300th term of the sequence below 57,66,75,84,93
Grace [21]
a_{300}=57+(300-1)\cdot9\\
a_{300}=57+299\cdot9\\
a_{300}=57+2691\\
a_{300}=2748
6 0
3 years ago
Read 2 more answers
Gulf gully and jump rope road are a pretty far distance.If the scale for the map is 0.5 inches=2.3 miles,what is the actual dist
Nezavi [6.7K]

Answer:

12 cm = 21.62 miles

6 cm = 11.04 miles

Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of \frac{map}{real world} and simplify.

We know \frac{map}{real world}=\frac{0.5in}{2.3 miles}. We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write \frac{4.7in}{xmiles} and  \frac{2.4in}{xmiles}

We set them equal.

\frac{0.5}{2.3}=\frac{4.7}{x}

and

\frac{0.5}{2.3}=\frac{2.4}{x}

To solve each proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

2.3(4.7)=0.5(x)\\10.81=0.5x\\\frac{10.81}{0.5}=\frac{0.5x}{0.5} \\21.62 miles=x

and

2.3(2.4)=0.5(x)\\5.52=0.5x\\\frac{5.52}{0.5}=\frac{0.5x}{0.5} \\11.04 miles=x

8 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
Use an inequality symbol to compare -3 +7____-10-2
Damm [24]

Answer:

-3+7 > -10-2

Step-by-step explanation:

-3+7 = +4

-10-2 = -12

∴ +4 > -12

7 0
3 years ago
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