A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have? Which of the following equations could be used to solve the problem?
2 answers:
<span>0.25x + 0.10(11-x) = 1.70 ←←←←←←←←←(This is the answer to your question)
25x + 10(11-x) = 170
25x + 110 - 10x = 170
15x + 110 = 170
15x = 60
x = 4
11-4 = 7 4=quarters 7=dimes 0.10 x + 0.25 ( 11 - x ) = 1.70
X - number of dimes, y - number of quarters 0.10 x + 0.25 ( 11 - x ) = 1.70
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