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3 years ago

Find value of x In x^2+2x

Mathematics

1 answer:

lara [203]3 years ago

6 0

Answer:

See explanation

Step-by-step explanation:

Assuming we want to solve for x in:

${x}^{2} + 2x = 0$

Then we factor to get:

$x(x + 2) = 0$

Apply the zero product principle to get:

$x = 0 \: or \: x + 2 = 0$

$x = 0 \: or \: x = - 2$

The question is not all that clear, so I assume you are solving for x in the completed quadratic equation.

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Look at this triangle work out length BC

Andreas93 [3]

Answer:

The length of BC is √105 cm or 10.2 cm.

Step-by-step explanation:

You have to apply Pythagoras Theorem, c² = a² + b² where c represents hypotenuse, a and b are the sides :

${c}^{2} = { a}^{2} + {b}^{2}$

$let \:a =BC \:, \: b = 8 \: , \: c = 13$

${13}^{2} = {BC}^{2} + {8}^{2}$

$169 = {BC}^{2} + 64$

${BC}^{2} = 169 - 64$

${BC}^{2} = 105$

$BC = \sqrt{105}$

$BC = 10.2 \: cm \: (3s.f)$

7 0

3 years ago

Read 2 more answers

HELP!! ALGEBRA QUESTION IN NEED OF SAVIOR PLEASE!! WILL GIVE 100 POINTS TO WHOEVER ANSWERS

galben [10]

Answer:

What is the question?

Step-by-step explanation:

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4 0

3 years ago

What is the standard form of the number below?

olasank [31]

Answer:

Where is the number??????

3 0

4 years ago

If UT is a midsegment of QRS, find SQ A. 8 B. 10 C. 16 D. 20

sladkih [1.3K]

If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3

Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.

8 0

3 years ago

Help please ASAP!!!!!!

dalvyx [7]

The answer is 5,3,3 in that order, you can do this using the point slope formula

5 0

3 years ago