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vivado [14]
3 years ago
14

Please help! I will not need help with the graph at the bottom just the equation

Mathematics
1 answer:
gladu [14]3 years ago
6 0

isolate y

move y to the right

4y=-2x-8

divide by 4

y = -1/2x -2

solution is

y=-1/2x-2

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A volleyball league organizer collected $2,040 for both divisions of volleyball teams.teams.the blue division costs &amp;160 per
evablogger [386]

A volleyball league organizer collected $2,040 for both divisions of volleyball teams. The Blue division costs $160 per team and the Red division cost $180 per team. How many teams will play in each division.

<h3><u>Answer:</u></h3>

6 teams will play in each division

<h3><u>Solution:</u></h3>

Given that volleyball league organizer collected $2,040 for both divisions of volleyball teams

The blue division costs $160 per team

The Red division cost $180 per team.

Let the number of blue teams be "b"

Let the number of red teams be "r"

Total cost = number of blue teams x cost of blue division per team + number of red teams x cost of red division per team

Total cost = 160b + 180r

2040 = 160b + 180r

Assuming both divisions have the same number of teams, we substitute b = r = x

2040 = 160x + 180x

2040 = 340x

x = 6

So 6 teams will play in each division

4 0
3 years ago
Does 26/3 equal 182/21
brilliants [131]

Answer: Yes, they are equal

Step-by-step explanation:

Quick statement: To find equivalent fractions, multiply or divide them by the same number.

In this particular example, you can divide 182 by 7 and get 26 and 21 by 7 to get 3. This symbols that they are equal. If you try the inverse operation (multiplication), you could multiply 26 by 7 and get 182. Same goes for 21 and 3: you multiply 3 by 7 to get 21. Just remember to multiply or divide the two numbers (numerator and denominator) by the same number to get an equivalent fraction.

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

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