Answer:
1662.768 --) rounded 1662.8
The critical values for a 90% confidence interval are approximately

, so the confidence interval in this case is roughly
<span> For this case we have an expression of the form:
</span>
![\sqrt[4]{16x^{11}y^8}/(81x^7y^6)](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B16x%5E%7B11%7Dy%5E8%7D%2F%2881x%5E7y%5E6%29%20)
To solve the problem, we must rewrite the expression using properties of exponents.
Rewriting the expression we have:
![\sqrt[4]{2^4x^8x^3y^8}/(81x^7y^6)](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B2%5E4x%5E8x%5E3y%5E8%7D%2F%2881x%5E7y%5E6%29%20)
Then, by root properties we have:
![2x^2y^2(\sqrt[4]{x^3})/(81x^7y^6) ](https://tex.z-dn.net/?f=%202x%5E2y%5E2%28%5Csqrt%5B4%5D%7Bx%5E3%7D%29%2F%2881x%5E7y%5E6%29%0A)
Then, by power properties again:
![2(\sqrt[4]{x^3})/(81x^5y^4)](https://tex.z-dn.net/?f=%202%28%5Csqrt%5B4%5D%7Bx%5E3%7D%29%2F%2881x%5E5y%5E4%29%20)
Answer:
An <span>expression that is equivalent is:
</span>
The radius is half the diameter, so your answer should be 6 m