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timurjin [86]
3 years ago
12

One​ month, two search engines were used to conduct a total of 3.52 billion online searches. Search engine A was used to conduct

0.66 billion more searches than search engine B. How many searches were conducted on each search​ engine?
FAST PLS
Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

Search Engine A = 2.09 billion searches.

Search Engine B = 1.43 billion searches.

Step-by-step explanation:

Engine A + Engine B = 3.52 billion

Search engine A was used to conduct 0.66 billion more searches than search engine B

A = 0.66 billon + B

Hence:

0.66 billion + B + B = 3.52 billion

2B = 3.52 billion - 0.66 billion

2B = 2.86 billion

B = 2.86 billion/2

B = 1.43 billion searches.

A = 0.66 billion + B

A = 0.66 billion + 1.43 billion

A = 2.09 billion searches.

Therefore:

Search Engine A = 2.09 billion searches.

Search Engine B = 1.43 billion

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7 0
3 years ago
Include work pleaseeeee
Angelina_Jolie [31]
Okay so to represent juice we are going to use X, and to represent water we are going to use Y.

We also know that the first two starting equations are:

6x + y = 135

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We can re-arrange the first equation so that it equals y (for now), so it is going to end up looking like this:

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Now divide by -8 on both sides

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3 years ago
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