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4 years ago

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A rectangular laundry hamper is 3 1⁄4 feet tall, 2 1⁄3 feet long, and 1 5⁄6 feet wide. What is the volume of the laundry hamper?

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1 answer:

Lady_Fox [76]4 years ago

5 0

One second while I awnser this question

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4(2g-3) = 5(g-2) how do you solve for g

raketka [301]

4(2g-3) = 5(g-2)

8g-12 = 5g-10

8g-5g = 12-10

3g = 2

g = 2/3

5 0

3 years ago

What is the inverse of the function f(x) = one-ninthx + 2?

Bumek [7]

Answer: 9x - 18

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y

$\text{Given: }\quad y=\dfrac{1}{9}x+2\\\\\text{Swapped: }x=\dfrac{1}{9}y+2\\\\.\qquad \quad x-2=\dfrac{1}{9}y\\\\.\qquad 9(x-2)=y\\\\.\quad \large\boxed{9x-18=y}$

3 0

3 years ago

PLS HELP! Will give 25 points!

RSB [31]

Answer and explanation:

Given: Belinda wants to invest $1,000. The table below shows the value of her investment under two different options for three different years:

Number of years 1 2 3

Option 1 (amount in dollars) 1100 1200 1300

Option 2 (amount in dollars) 1100 1210 1331

To find:

Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2?

Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years.

Part C: Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1?

Solution:

Part A: Linear and exponential functions can be used to describe the value of the investment after a fixed number of years using option 1 and option 2, respectively.

Part B: (n=n+100) and (n=n+100x) are the functions for each option to describe the value of the investment f(n), in dollars, after n years.

Part C: Yes, there will be a significant difference of 1900 in the value of Belinda's investment after 20 years if she uses option 2 over option 1.

Part A:

In the case of option 1, the linear function can be used to describe the value of the investment after a fixed number of years. This is because, in option one, the amount increases by a fixed amount every year.

In the case of option 2, the exponential function can be used to describe the value of the investment after a fixed number of years. This is because, in option 2, the amount increase is higher than last year.

Part B:

For option 1, the function is

For option 2, the function is

Here, x is the increase in amount every consecutive year.

Part C:

After 20 years, the amount from option 1 would be 3000 and the amount from option 2 would be 4900. Thus, there is a difference between 1900.

Therefore,

Part A: Linear and exponential functions can be used to describe the value of the investment after a fixed number of years using option 1 and option 2, respectively.

Part B: (n=n+100) and (n=n+100x) are the functions for each option to describe the value of the investment f(n), in dollars, after n years.

Part C: Yes, there will be a significant difference of 1900 in the value of Belinda's investment after 20 years if she uses option 2 over option 1.

Hope this helps

8 0

2 years ago

A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase

Xelga [282]

Answer:

$\mathbf{S(t)=200(\frac{105}{100})^{x}}$

$\mathbf{A(t)=40(\frac{98}{100})^{x}}$

$\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}$

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.

A function 'S(t)' which gives the number of students in school after 't' years.

S(0) means the initial year when the number of students is 200.

S(0) = 200

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.

S(1) = 200 + 5% of 200 = $200+\frac{5}{100}\time200$ = $200(1+\frac{5}{100})$ = $200(\frac{105}{100})$

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)

S(2) = S(1) + 5% of S(1) = $\textrm{S}(1)(\frac{105}{100})$ = $200(\frac{105}{100})(\frac{105}{100})$ = $200(\frac{105}{100})^{2}$

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Similarly $\mathbf{S(x)=200(\frac{105}{100})^{x}}$

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.

A function 'A(t)' which gives the amount spend on each student in school after 't' years.

A(0) means the initial year when the number of students is 40.

A(0) = 40

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.

A(1) = 40 + 2% of 40 = $40-\frac{2}{100}\time40$ = $40(1-\frac{2}{100})$ = $40(\frac{98}{100})$

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)

A(2) = A(1) + 2% of A(1) = $\textrm{A}(1)(\frac{98}{100})$ = $40(\frac{98}{100})(\frac{98}{100})$ = $40(\frac{98}{100})^{2}$

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Similarly $\mathbf{A(x)=40(\frac{98}{100})^{x}}$

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) × (amount spend on each student)

E(t) = S(t) × A(t)

$\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}$

$\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}$

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

6 0

3 years ago

Read 2 more answers

What is 1.086 rounded to the nearest whole number

Sphinxa [80]

1.086 rounded to the nearest whole number is 1

5 0

4 years ago