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3 years ago

15

A rectangular laundry hamper is 3 1⁄4 feet tall, 2 1⁄3 feet long, and 1 5⁄6 feet wide. What is the volume of the laundry hamper?

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1 answer:

Lady_Fox [76]3 years ago

5 0

One second while I awnser this question

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mann middle school has 1,000 students, 40 teachers, and 5 administrators. if the school grows to 1,200 students and the ratios a

gregori [183]

6 administrators are needed

7 0

3 years ago

For every 5 coins carmen gets ,she gives 2 to her brother Frankie.If carmen has 9 coins,howmany coins does Frankie have?

FrozenT [24]

Answer:

Frankie have 6 coins

Step-by-step explanation:

For every 5 coins Carmen gets ,she gives 2 to her brother Frankie

Out of 5 coins, Carmen given 2 to her brother Frankie

So Carmen has 3 coins and Frankie has 2 coins

Ratio of coins , Frankie to Carmen is

2: 3

We need to find the number of coins Frankie has if Carmen has 9 coins

ratio of Frankie to Carmen is x : 9

Now make a proportion and solve for x

$\frac{2}{3} =\frac{x}{9}$

Cross multiply it

2*9 = 3*x

18 = 3x

Now divide both sides by 3

so x= 6

Frankie have 6 coins

7 0

3 years ago

The floor of a storage unit is 6 ft long and 8 feet wide what is the distance between two opposite corners of the floor

riadik2000 [5.3K]

Answer:

10 ft

Step-by-step explanation:

Use theorem pythagoras

Length = x

${x}^{2} = 8 {}^{2} + {6}^{2} \\ x = - 10 \\ x = 10$

the answer is 10 because length can't be in negative number

4 0

3 years ago

A circular swimming pool has a diameter of 40 meters. The depth of the pool is constant along west-east lines and increases line

Nataliya [291]

Answer:

Volume is $2000\pi\ m^{3}$

Solution:

As per the question:

Diameter, d = 40 m

Radius, r = 20 m

Now,

From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:

iff

h(y) = cy + d

Then

when y = 1 m

h(- 20) = 1 m

1 = c.(- 20) + d = - 20c + d (1)

when y = 9 m

h(20) = 9 m

9 = c.20 + d = 20c + d (2)

Adding eqn (1) and (2)

d = 5 m

Using d = 5 in eqn (2), we get:

$c = \frac{1}{5}$

Therefore,

$h(y) = \frac{1}{5}y + 5$

Now, the Volume of the pool is given by:

$V = \int h(y)dA$

where

A = $r\theta$

$A = rdr\ d\theta$

Thus

$V = \int (\frac{1}{5}y + 5)dA$

$V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}rsin\theta + 5) rdr\ d\theta$

$V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}r^{2}sin\theta + 5r}) dr\ d\theta$

$V = \int_{0}^{2\pi} (\frac{1}{15}20^{3}sin\theta + 1000) d\theta$

$V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}$

$V = 0 + 2\pi \times 1000 = 2000\pi\ m^{3}$

7 0

3 years ago

The diffrence between an integer p and (-5) is 1 find the value of p

Nastasia [14]

Solution:

<u>Note that:</u>

Given sentence: The difference between an integer p and (-5) is 1.

<u>Let's reread the sentence carefully.</u>

The difference between an integer p and (-5) is 1.

=> p - (-5) = 1

<u>Change the sign.</u>

p - (-5) = 1
=> p + 5 = 1

<u>Subtract 5 both sides:</u>

p + 5 = 1
=> p + 5 - 5 = 1 - 5
=> p = -4

4 0

2 years ago