Find the slope of the line passing through the points (-6,5) and (-6,-8)
1 answer:
You might be interested in
The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.
It is given that the standard normal curve shows the shaded area in the curve.
It is required to find the approximate area of the unshaded region under the standard normal curve.
<h3>What is a normal distribution?</h3>It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.
In the curve showing the shaded region area between:
First, we calculate the shaded region area:
From the data given the value of Ф(1) = 0.8413.
P(Z<1) = 0.8413 and
P(Z<2) = 0.9772
The area of the shaded region:
= P(Z<2) - P(Z<1)
= 0.9772 - 0.8413
= 0.1359
The area of the unshaded region:
= 1 - The area of the shaded region ( because the curve is symmetric)
= 1 - 0.1359
= 0.8641 ≈ 0.86
Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.
Know more about the normal distribution here:
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
