ALL of their points are common. If you multiply each side of the first equation by 2, you'll see that they're both the same line.
ANSWER

EXPLANATION
The equation of the curve is:


We differentiate to obtain:


The length of the arc

This implies that:



<em>There are 201 10's in 2010. Find how many tens are in 2000 (multiply 10 by 200) and then add 10 for the 10 in 2010. There are 201 tens.</em>
This is a right triangle so the total angle is 90 degrees.
90 degrees - 20 degrees = 70 degrees, so 2x = 70
2x/2= 70/2
X= 35