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Inessa [10]
3 years ago
8

Records kept by the chief dietitian at the university cafeteria over a 28-period show the following weekly consumption of milk (

in gallons). Milk 200 205 210 215 220 225 230 235 240 Weeks 2 5 6 3 5 2 2 2 1 (a) Find the average number of gallons of milk consumed per week in the cafeteria. (Round your answer to the nearest whole number.)
Mathematics
2 answers:
Radda [10]3 years ago
8 0

Answer:

Step-by-step explanation:

lora16 [44]3 years ago
6 0

Answer:

220

Step-by-step explanation:

To find the average, add all values then divide by how many values are included

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On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be
Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0
2 years ago
A used bookstore sells hardback books and paperback books.A hardback book costs $11, including tax.A paperback book costs $5, in
Ket [755]

Answer:

D.5

Step-by-step explanation:

You can write the following equations from the information given:

y=x+3 (1)

11x+5y=47 (2)

x is the number of hardback books

y is the number of paperback books

You can replace (1) in (2):

11x+5(x+3)=47

11x+5x+15=47

16x=47-15

16x=32

x=32/16

x=2

Then, you can replace the value of x in (1) to find the value of y:

y=2+3

y=5

According to this, the answer is that Jamal bought 5 paperback books.

6 0
3 years ago
What is the product (2t+1) (t-4)
____ [38]

Answer:

Step-by-step explanation:

(2t+1)(t-4)

= 2t^2 - 8t + t - 4

= 27^2 - 7t - 4

3 0
2 years ago
To find 10, Beau found 32 = 9 and 42 = 16. He said that since 10 is between 9 and 16, 10 is between 3
AlexFokin [52]

Given that:

Consider it is \sqrt{10} instead of 10 on two places.

\sqrt{10} is between 3  and 4. So, Beau thinks a good estimate for \sqrt{10} is = 3.5.

Solution:

To find \sqrt{10}, Beau found 3² = 9 and 4² = 16.

He said that since 10 is between 9 and 16.

Since 10 is close to 9, therefore \sqrt{10} must be close to 3. So, Beau's estimate is high.

Now,

(3.1)^2=9.61

(3.2)^2=10.24

Since, 10 lies between 9.61 and 10.24, therefore \sqrt{10} must be lies between 3.1 and 3.2.

\dfrac{3.1+3.2}{2}=3.15

Therefore, the estimated value of \sqrt{10} is 3.15.

4 0
3 years ago
If x = 3 in.and Y = 4 in.and what is the perimeter of the polygon blank in.
vivado [14]

Please provide more information. You need to add the sides of the polygon to find the perimeter.

4 0
3 years ago
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