Answer:
Hi, I'm going to put the code answer here and you put in the corresponding line to not copy all the code in the answer.
replace the following line or adjust to the following code
/*
* CODE HERE
while(personSelect <= 0 || personSelect > 5) {
System.out.println("Wrong number, try to input the number in range 1 to 5" );
personSelect = scan.nextInt();
}
if(personSelect == 1){
person1.setGpa(newGPA);
printInfo()
}
else if(personSelect == 2){
person2.setGpa(newGPA);
printInfo()
}
else if(personSelect == 3){
person3.setGpa(newGPA);
printInfo()
}
else if(personSelect == 4){
person4.setGpa(newGPA);
printInfo()
}
else {
person5.setGpa(newGPA);
printInfo()
}
*/
Explanation:
According to the description of code, we have to add some lines to resolve the questions.
a):
In base on the input, we have to modify the <em>attribute GPA</em> with the method <em>setGpa</em> depending on the person chosing. We call the person chosen before and also call the method setGpa( ) and pass as <em>parameter</em> the GPA value obtained in tha last input
b)
In this case we have to <em>create a loop</em> for iterate the times that is necesary to get a value of person that is permit in <em>range 1 to 5</em>, and hence that we create and individual if condition to assign the GPA to the person chosen.
I hope it's help you.
Answer:
Encryption Keys
Explanation:
In order to make sure only the intended recipient receives the information, encryption keys rely on a unique pattern, just like your house key, except instead of grooves and ridges encryption keys use numbers and letters.
MOHR-COULOMB FAILURE CRITERIA:
In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.
If you can not understand the below symbols see the attachment below
f f ()
Where: f = Shear Stress on Failure Plane
´= Normal Stress on Failure Plane
See the graph in the attachment
For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula: shear stress = f c tan
Where,
• f is Shear Stress on Failure Plane
• c is Cohesion
• is Normal Total Stress on Failure Plane
• is Friction Angle
