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erica [24]
3 years ago
8

Draw a flow chart that accepts mass and volume as input from the user. The flow chart should compute and display the density of

the liquid.( Note: density = mass/volume ).​

Computers and Technology
1 answer:
TiliK225 [7]3 years ago
6 0

Answer:

See attachment for flowchart

Explanation:

The flowchart is represented by the following algorithm:

1. Start

2. Input Mass

3. Input Volume

4 Density = Mass/Volume

5. Print Density

6. Stop

The flowchart is explained by the algorithm above.

It starts by accepting input for Mass

Then it accepts input for Volume

Step 4 of the flowchart/algorithm calculated the Density using the following formula: Density = Mass/Volume

Step 5 prints the calculated Density

The flowchart stops execution afterwards

Note that the flowchart assumes that the user input is of number type (integer, float, double, etc.)

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Write a client program that writes a struct with a privateFIFO name (call it FIFO_XXXX, where XXXX is the pid that you got from
ivann1987 [24]

Answer:

client code:

#include <stdio.h>

#include <fcntl.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include <stdlib.h>

#include <string.h>

int main (void)

{

 struct values

 {

   char privateFIFO[14];

   int intbuff;

 }input;

 int fda;  // common FIFO to read to write to server

 int fdb;      // Private FIFO to read from server

 int clientID;

 int retbuff;

 char temp[14];

 clientID = getpid();

 strcpy(input.privateFIFO, "FIFO_");

 sprintf(temp, "%d", clientID);

 strcat(input.privateFIFO, temp);

 printf("\nFIFO name is %s", input.privateFIFO);

 // Open common FIFO to write to server

 if((fda=open("FIFO_to_server", O_WRONLY))<0)

    printf("cant open fifo to write");

 write(fda, &input, sizeof(input));    // write the struct to the server

 close(fda);

 // Open private FIFO to read

 if((fdb=open(input.privateFIFO, O_RDONLY))<0)

    read(fdb, &retbuff, sizeof(retbuff));

 printf("\nAll done\n");

 close(fdb);

}

server code:

#include <stdio.h>

#include <errno.h>

#include <fcntl.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include <stdlib.h>

#include <string.h>

struct values

 {

   char privateFIFO[14];

   int intbuff;

 }input;

int main (void)

{

 int fda;  //common FIFO to read from client

 int fdb;  //private FIFO to write to client

 int retbuff;

 int output;

// create the common FIFO  

 if ((mkfifo("FIFO_to_server",0666)<0 && errno != EEXIST))

       {

       perror("cant create FIFO_to_server");

       exit(-1);

}

// open the common FIFO

 if((fda=open("FIFO_to_server", O_RDONLY))<0)

    printf("cant open fifo to write");

output = read(fda, &input, sizeof(input));

// create the private FIFO

 if ((mkfifo(input.privateFIFO, 0666)<0 && errno != EEXIST))

 {

   perror("cant create privateFIFO_to_server");

   exit(-1);

 }

 printf("Private FIFO received from the client and sent back from server is: %d", output);

 //open private FIFO to write to client

if((fdb=open(input.privateFIFO, O_WRONLY))<0)

   printf("cant open fifo to read");

 write(fdb, &retbuff, sizeof(retbuff));

 close(fda);

 unlink("FIFO_to_server");

 close(fdb);

 unlink(input.privateFIFO);

}

Explanation:

3 0
3 years ago
Write an exception class named InvalidTestScore. Modify the TestScores class you wrote in Part I so that it throws an InvalidTes
Elan Coil [88]

Answer:

See Explaination

Explanation:

package testscores;

import java.util.ArrayList;

import java.util.List;

public class TestScores {

public List<Integer> scorearray=new ArrayList<>();

public TestScores(List<Integer> scores) throws InvalidTestScore{

this.scorearray=scores;

for(int i=0;i<scorearray.size();i++){

if(scorearray.get(i)>100 || scorearray.get(i)<0){

throw new InvalidTestScore(this.scorearray.get(i));

}

}

}

public double average(){

int tot=0;

for(int i=0;i<this.scorearray.size();i++){

tot=tot+this.scorearray.get(i);

}

return tot*(1.0)/(this.scorearray.size());

}

class InvalidTestScore extends Exception

{

private double amount;

public InvalidTestScore(int Score)

{

System.out.println("Invalid Score "+Score);

}

}

}

8 0
3 years ago
Write a function called play_round that simulates two people drawing cards and comparing their values. High card wins. In the ca
elena-s [515]

Answer:

Here you go, Change it however you'd like :)

Explanation:

import random as r

def play_round(p1, p2):

   cards = [1,2,3,4,5,6,7,8,9,10,"J","Q","K","A"]

   play1 = r.choice(cards)

   play2 = r.choice(cards)

   

   while play1 == play2:

       play1 = r.choice(cards)

       play2 = r.choice(cards)

   

   if cards.index(play1) > cards.index(play2):

       return f"{p1}'s Card: {play1}\n{p2}'s Card: {play2}\nThe Winner is {p1}"

   else:

       return f"{p1}'s Card: {play1}\n{p2}'s Card: {play2}\nThe Winner is {p2}"

print(play_round("Bob","Joe"))

8 0
3 years ago
Mike gets along with his co-workers and is always helpful to the clients. He demonstrates good _____.
pishuonlain [190]
I think the answer is A
5 0
3 years ago
Read 2 more answers
What are the values of the following expressions? In each line assume that,
MissTica

Answer:

double x = 2.5;

double y = -1.5;

int m = 18;

int n = 4;

string s = "Storm";

string t = "Watch";

The output of the expression "x + n*y - (x+n)*y" is "6.25".

and the output of expression "m/n + m%n" is "6".

Explanation:

for the first expression,

x + n*y - (x+n)*y ,put value of every variables in it.

=2.5+4*(-1.5)-(2.5+4)*(-1.5)

=2.5-6.0-(6.5*(-1.5)

=-3.5+9.75

=6.25

for the second expression,

m/n + m%n,  put value of every variables in it.

=18/4 +18%4

=4+2      ("/ will give quotient and % will give remainder")

=6

4 0
3 years ago
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