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Burka [1]
4 years ago
14

What is 6.302 rounded to the nearest tenth?

Mathematics
2 answers:
solmaris [256]4 years ago
5 0

Answer:

6.3

Step-by-step explanation:

\huge \: 6.302 \approx \: 6.3

Oxana [17]4 years ago
4 0

Answer:

6.3

Step-by-step explanation:

rounding off to nearest tenths means to one decimal place.

we have to consider the number in the hundredths place value, which is (0)

0 - is less than 5, so we do not add one to the tenths place value.

the answer therefore is 6.3

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3 years ago
Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

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3 years ago
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Answer:

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841 = c^2

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6 0
3 years ago
Read 2 more answers
Ashley has sold 70% of the 20 candy bars she has to. How many candy bar's does she have left to sell
yawa3891 [41]
She has 6 left.
70%= 0.7
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OR
30%=0.3
0.3 x 20= how many she hasn't sold (6)


4 0
3 years ago
Read 2 more answers
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