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lisabon 2012 [21]
3 years ago
12

Please solve the problem below

Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0
You would use the cosine rule for this as you have 2 lines and are given the angle between them
The angle can be figured out easily as the clock has 12 equal components, meaning each component is 360/12 which is 30
As there are 5 components between A and B the angle is 30*5 =150
You can plug all of this into the cosine rule
a^2= b^2+c^2-2bcCos(A)
So a = sqrt( 10^2 +7^2 -(2*10*7) cos150)
a=16.4 to 3 sf
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Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
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Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

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  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

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  • Event B: Fair coin.

The probability associated with 3 heads are:

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Hence:

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The probability of 3 heads and the fair coin is:

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Then, the conditional probability is:

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0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

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