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Alchen [17]
4 years ago
13

Determine whether the conjecture is true or false. If false, give a counterexample.

Mathematics
2 answers:
S_A_V [24]4 years ago
5 0
I think it is False, x=2

Contact [7]4 years ago
3 0

We start with the given equation

x^{2} + 4 = 8

Now, we solve the equation, we subtract 4 on either side,

x^{2} +4 -4 = 8-4

x^{2}  = 4

x = \sqrt{4}

\sqrt{4 }  = +2 and -2

x = +2 or -2

So, x= +2 and x =-2

Since the given conjuncture says X=-2, we can conclude that the given conjuncture is TRUE

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Maria's family drove 140 mi to her grandparents' house and averaged 56 ​ mi/h ​ on the way there. On the return trip, they avera
GaryK [48]

Answer: 5.3 Hours


Step-by-step explanation: 140 mi there at 56 mi per hour would be 2.5 hours. Then back 140 mi at 50 mi/h would be 2.8. 2.5 plus a 2.8 is 5.3 hours


4 0
3 years ago
Each member of the swim team must pay $76 to join the team. There are 376 members. How much does the team receive in dues?
Basile [38]

Answer:

$28,576

Step-by-step explanation:

$76 (amount that each member pays) * 376 (total members) = $28,576 (amount that will be received in dues)

I hope this helps :)

7 0
3 years ago
Help please I don’t get it
AlexFokin [52]

Answer:

3/8

Step-by-step explanation:

Rearrange, find common denominator.

x =  \frac{7}{8}  -  \frac{1}{2}  \\ x =  \frac{7}{8}  -  \frac{4}{8}  \\ x =  \frac{3}{8}

8 0
3 years ago
Read 2 more answers
How to solve <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B4%7D%20x%20%7B%7D%5E%7B2%7D%20%20%3D%20x%20%2B%202" id="TexFormu
Vikentia [17]

Answer:

➩ x=2,-\frac{2}{3}

Step-by-step explanation:

\sqrt{4x^2}=x+2

➨ We can also solve by completing both squares, however. Since we can pull out the square root.

\sqrt{4x^2}=|2x| ➩ Define of Absolute Value/Square Root

➩ \sqrt{x^2}=|x|

Thus, our new equation is ➩ |2x|=x+2

To solve an absolute-value equation, let there be two conditions.

➨ Where x ≥ 0

2x=x+2\\

Move x to another side

2x-x=2\\x=2

➨ Where x < 0

-2x=x+2\\-2x-x=2\\-3x=2\\x=\frac{2}{-3}\\x=-\frac{2}{3}

3 0
3 years ago
Formula for the volume of a square pyramid, v=1/3lwh for w
tatuchka [14]

\dfrac{1}{3}lwh=V\qquad|\text{multiply both sides by 3}\\\\lwh=3V\qquad|\text{divide both sides by}\ lh\neq0\\\\\boxed{w=\dfrac{3V}{lh}}

3 0
4 years ago
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