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nikklg [1K]
4 years ago
13

Please help ;u;

Mathematics
1 answer:
FromTheMoon [43]4 years ago
8 0
The correct answer is 4. hope this helps ((:
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Layna can paint a 350-square foot room in 4 hours. It takes Bebe 7 hours to paint the same room. Which equation can be used to f
ohaa [14]

The equation can be used to find the time in hours, \dfrac{t}{4}+\dfrac{t}{7}=1 and the time will be 2.5 hours. So the correct answer is option A.

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Layna can paint a 350-square-foot room in 4 hours.It takes Bebe 7 hours to paint the same room.

Let t be the total time taken by both to paint.They are completing 1 job so the equation will be :

\dfrac{t}{4}+\dfrac{t}{7}=1

Further solving it we get;

7 t + 4 t = 28

11t  =  28

t = 2.5 hours.

Therefore the equation can be used to find the time in hours, \dfrac{t}{4}+\dfrac{t}{7}=1 and the time will be 2.5 hours. So the correct answer is option A.

To know more about equations follow

brainly.com/question/2972832

#SPJ1

8 0
2 years ago
What the equivalent fraction 1/3
emmasim [6.3K]
2/6, 3/9, 4/12, 5/15, 6/18, 7/21, 8/24 etc.
7 0
4 years ago
Read 2 more answers
25-foot wire connects the top of a utility pole to a point on the ground located 7 feet away from the base of the pole.
marta [7]

Answer:

B. 24 ft.

Step-by-step explanation:

25 would be the hypotenuse of a triangle and 7 is a leg, so

7^2 + x^2 = 25^2

49 + x^2 = 625

x^2 = 576

x = 24 ft

8 0
3 years ago
Read 2 more answers
Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
Arisa [49]

Answer: S_n=5(1-\dfrac{1}{n+1}) ; 5

Step-by-step explanation:

Given series : [\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]

Sum of series = S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]

Consider \dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}

=\dfrac{1}{n}-\dfrac{1}{n+1}

⇒ S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]

Put values of n= 1,2,3,4,5,.....n

⇒ S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})

All terms get cancel but First and last terms left behind.

⇒ S_n=5(1-\dfrac{1}{n+1})

Formula for the nth partial sum of the series :

S_n=5(1-\dfrac{1}{n+1})

Also, \lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})

=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5

4 0
3 years ago
-1 +(-3) is units from -1 in the direction
likoan [24]

Answer:

-4

Step-by-step explanation:

5 0
4 years ago
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