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Airida [17]
2 years ago
8

How many solutions does the following equation have? 10x-1=10x+4

Mathematics
2 answers:
zimovet [89]2 years ago
7 0
  • Your answer is no solution.
  • Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
  • 10x - 1 = 10x +4
  • or, 10x - 10x = 4 + 5
  • or, 0 = 9
  • Hence, the equation has <em><u>no solution</u></em>.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Alenkinab [10]2 years ago
7 0

Answer:

10x-1=10x+4

10x-10x=4+1

x=5

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The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

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The formula for estimating the population proportion by a confidence interval is given by:

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Where:

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<u>First</u> we compute the \hat{p} value:

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Now we can replace in the formula with the obtained values to compute the confidence interval:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)

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3 years ago
Q(a+1) - 2q(a) if q(x) = x²+3x+4​
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q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

Thanks for watching buddy good luck.

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