
<u>Ratio of two angles are 6:13.</u>
So, let the one angle be
and another be 
As we know that,
Sum of all interior angles of a quadrilateral = 
So let's sum up the given angles,






Hence, 
So, First angle

Second angle

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Hope it helps you:)
Answer & Step-by-step explanation:
So I can't exactly graph exactly, but I'll try...
To solve:
x+11<6 Subtract 11 on both sides.
x<-5
To graph:
<-------|---------o---------|-------->
-6 -5 -4
(The bolded part of the line is the side you shade the graph on. In case you can't see it, you have to shade the left side of the open circle.)
Hope this helps! Have an awesome day ( • ω • )^
Oh idk and idc cuz i just really don’t so yea
It’s the first one. I think
ANSWER : it is a right angle