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dalvyx [7]
4 years ago
15

What would it be and what would it be if I round it to the nearest hundreds

Mathematics
1 answer:
crimeas [40]4 years ago
5 0

The answer to your question is 1.36

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What is the value of x in the equation 3/4x+4=5/8
Radda [10]
\frac{3x}{4} +4= \frac{5}{8}
Multiply both sides by 8.
2(3x) + 8(4)= 5
6x+32=5
Subtract 32 from both sides
6x=-27
Divide both sides by 6.
x=-27/6
Simplify
x=-9/2

Answer: x=-9/2
8 0
3 years ago
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A boy is training to run a marathon. Every day he puts on his sneakers and runs 12 miles. The boy never misses a day. How many m
tangare [24]
4380 miles in a yerrrr

3 0
3 years ago
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I am a fraction equivalent to 6/8 my numerator is 16 less than my denominator what fraction am i
Paul [167]

Answer:

The answer is

\frac{48}{64}

Step-by-step explanation:

Equivalent fractions are set of fractions which have the same value when simplified.

The equivalent fraction to 6/8 whose numerator is 16 less than its denominator can be obtained through two basic methods below.

<u>Method 1</u>

Multiply the numerator and denominator by 8 respectively.

\frac{6}{8}  =  \frac{6 \times 8}{8 \times 8}  =  \frac{48}{64}

The numerator being 16 less than the denominator is:

48 - 64 =  - 16

<u>Method 2</u>

Find the equivalent fraction to 6/8 whose numerator is 16 less than its denominator by continuous multiplication approach. In other words, multiply 6/8 till you arrive at an equivalent fraction whose numerator is 16 less than its denominator. Simply multiply 6/8 by 2, 3, 4, 5, 6, 7, 8. Thus:

\frac{6}{8}  =  \frac{12}{16}  =  \frac{18}{24}  =  \frac{24}{32}  =  \frac{30}{40}  =  \frac{36}{48}  =  \frac{42}{56}  =  \frac{48}{64}

The difference between the numerator and denominator of the equivalent fractions are: -2, -4, -6, -8, -10, -12, -14, -16

Hence, 48/64 is the equivalent fraction to 6/8 whose numerator and denominator difference is less than 16.

That is,

\frac{6}{8}  =  \frac{48}{64}

Such that 48 - 64 = -16.

8 0
3 years ago
The area of a trapezoid is given by the equation A = 1/2 * h(b1 + b2), where h is the height and b1 and b2 are the lengths of th
masya89 [10]

Answer:

A = 78 cm²

Step-by-step explanation:

substitute h = 6 , b₁ = 6, b₂ = 10 into the formula

A = \frac{1}{2} × 6 × (6 + 10) = 3 × 26 = 78 cm²

6 0
2 years ago
The lifetime of a lightbulb can be modeled with an exponential random variable with an expected lifetime of 1000 days. (a) Find
astraxan [27]

Answer:

a) 0.13533

b) 0.36788

Step-by-step explanation:

Let X be the random variable that measures the lifetime of a bulb.

If the random variable X is exponentially distributed and X has an average value of 1000 days, then its probability density function is

\bf f(x)=\frac{1}{1000}e^{-x/1000}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/1000}

(a) Find the probability that the light bulb will function for more than 2000 days

\large P(X>2000)=1-P(X\leq 2000)=\\\\=1-(1-e^{-2000/1000})=e^{-2}=0.135335

(b) Find the probability that the light bulb will function for more than 2000 days, given that it is still functional after 500 days

Let A and B be the events,

<em>A = “The bulb will last at least 2000 days” </em>

<em>B = “The bulb will last at least 500 days” </em>

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\large P(A | B) = P(B)P(B) = (P(B))^2

We have  

\large P(B)=P(X \geq 500)=1-P(X\leq 500)=1-(1-e^{-500/1000})=e^{-0.5}=0.60653

hence,

\large P(A | B)=(P(B))^2=(0.60653)^2=0.36788

5 0
3 years ago
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