The area of the triangle is A= (1/2)absinγ
(sinγ)Λ2+(cosγ)Λ2=1 => sinγ=√1-(cosγ)∧2= √1- (1/4)∧2=√1-(1/16)=√(15/16)=√15/4
A=(1/2)*6*7*√15/4=21*√15/4=(21/4)√15
Good luck!!!
Answer:
d
Step-by-step explanation:
Since DF = EF then the triangle is isosceles with base angle being congruent, that is
∠ D = ∠ E , then
∠ D =
=
= 23.5°
Answer
Find out the what is the ratio of students with pets to students without pets .
To prove
As given
of 60 students, 24 students have a pet.
Thus Total number of student = 60
students have pets = 24
students without pets = 60 - 24
= 36
Now ratio of students with pets to students without pets .

simplify the above

Therefore the ratio of students with pets to students without pets be 2:3 .
Hence proved
Answer:
9.56 ft/sec
Step-by-step explanation:
We are told that a 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec.
I've attached an image showing triangle that depicts this;
Thus; dx/dt = 3.4 ft/sec
From the attached image and using principle of similar triangles, we can say that;
9/y = 5.8/(y - x)
9(y - x) = 5.8y
9y - 9x = 5.8y
9y - 5.8y = 9x
3.2y = 9x
y = 9x/3.2
dy/dx = 9/3.2
Now, to find how fast the tip of the shadow is moving away from the lamp post, it is;
dy/dt = dy/dx × dx/dt
dy/dt = (9/3.2) × 3.4
dy/dt = 9.5625 ft/s ≈ 9.56 ft/sec