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Colt1911 [192]
3 years ago
8

20x -10x to the second power + 5x to the third power . In descending order

Mathematics
1 answer:
mario62 [17]3 years ago
7 0
It'd be best if you'd stick to symbols.  My interpretation of what you've typed here is 20x - 20x^2 + 5x^3.  In descending order by powers of x, that gives us

5x^3 - 20x^2 + 20x.
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X ^-4 + x ^ 3 - 4x ^ 2 = 2x - 4
Lady bird [3.3K]

Answer:

Ok, If you are trying to solve for x then your answer in fraction form is x=4/11. If you want it in decimal form the answer is 0.36(Repeats forever). And these answers are also implying that when you typed a  "^" it meant multiplcation

Step-by-step explanation:

I have used an Online Algebra Calculator to help guide me to my answer and this answer is 100% correct so,

PLEASE MARK BRAINLIEST

4 0
3 years ago
Arrange the following numbers in order from least to greatest.<br><br>7, 7.1, 7.2, √51<br>​
never [62]

Answer:

7, 7.1, √51, 7.2

Step-by-step explanation:

√51 is 7.14

5 0
3 years ago
Why cant i see the option to ask for a tutor:( is night time that's why? please answer ​
Aleks [24]

Answer:

It wont let me eat either day or night I cant get one?

5 0
3 years ago
Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3
AlexFokin [52]
The ODE is separable, i.e. you can write

\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx

Integrating both sides gives the general solution.

\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx
y=-\ln|\cos x|+C

Given that y\left(\dfrac\pi4\right)=3, we have

3=-\ln\left|\cos\dfrac\pi4\right|+C
3=-\ln\dfrac1{\sqrt2}+C
3-\ln\sqrt2=C


and so the particular solution to the IVP is

y=-\ln|\cos x|+3-\ln\sqrt2
y=3-\ln|\sqrt2\cos x|
4 0
3 years ago
PLZ HEEEELP!!!!! 10 POINTS!!!!
katrin2010 [14]

Answer:

Step-by-step explanation:

Part a

We need two inequalities, one for time worked at each job and the other

for amounts of money earned.

time:  Let b and c represent the time (number of hours) worked at babysitting and landscaping respectively.  Then b + c ≤ 20 hrs/wk

earnings:  Let ($3/hr)(b) represents the amount of money earned babysitting for b hour.  Let  ($7/hr)(c) represent the money earned working at landscaping.  These amounts are <em>per week</em>.  The appropriate inequality is  ($3/hr)(b) +  ($7/hr)(c) ≥ $84 per week.  The other inequality is

b + c ≤ 20 hrs/wk.

Part b:

As before, b + c ≤ 20 hrs/wk.  What happens if Chet spends all his 20 hours babysitting?  To answer this, set c = 0 (no landscaping hours).  Then b ≤ 20 hours.  At $3/hr, he could earn only $60 and have no time left for landscaping.  Not good.

Let's experiment:  suppose he works 15 hours babysitting and 5 hours landscaping.  His earnings would be $45 + $35, or $80.  Still not enough; he wants to earn $84 total.    Let's redistribute his time and try again:  suppose he works 14 hours babysitting and 6 hours landscaping; his earnings would be $42 + $42, or $84.  So {b = 14 hours and c + 6 hours} is a solution.  As we continue to reduce the number of hours Chet works babysitting and correspondingly increase those he works landscaping, his earnings will go up, beyond $84.

Here's a table that summarizes this:

babysitting          landscaping    total amount

  hours                   hours               earned

      15                          5                      $60 (not acceptable)

       14                         6                       $84 (borderline acceptable)

       12                          8                       $36 + $42 = $78 (great)

        6                          14                       $116 (greater still)

         2                          18                     $132

          1                           19                      $134

          0                          20                      $140

Summary:  Chet can work anywhere from 0 to 14 hours babysitting and expect to earn $84 or more.

4 0
3 years ago
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