Answer:
∠T = 67.5
∠V = 22.5
Step-by-step explanation:
Angles of a triangle rule: The angles of a triangle should add up to equal 180
That being said we create an equation to solve for x
180 = 3x + x + 90 ( there is a right angle indicated by the square at the bottom right of the triangle. A right angle has a measure of 90 degrees so that is where the 90 cam from )
Now that we've created an equation we want to solve for x
180 = 3x + x + 90
step 1 combine like terms
3x + x = 4x
now we have 180 = 4x + 90
step 2 subtract 90 from each side
180 - 90 = 90
now we have 90 = 4x
step 3 divide each side by 4
4x / 4 = x
90 / 4 = 22.5
we're left with x = 22.5
Now we want to find ∠T and ∠V
To do so we replace x in the given expressions with 22.5
for ∠V
∠V = x so ∠V = 22.5
for ∠T
∠T = 3x
* replace x with 22.5 *
3 (22.5) = 67.5
Hence ∠T = 67.5
Answer:
- The radius is r = 3 in,
- The height is h = 4 in
<u>The area of the base:</u>
- A(b) = πr² = π(3²) = 9π in²
<u>The circumference of the base:</u>
<u>The area of the lateral surface:</u>
- A(l) = Ch = 6π(4) = 24π in²
<u>The surface area:</u>
- S = 2A(b) + A(l) = 2*9π + 24π = 42π in²
Answer:
Step-by-step explanation:
Slope of perpendicular lines = -1
y = 5/2x + 3

-1 ÷ 
= 
(-3 , -5)
Equation of the required line: y - y₁ = m(x -x₁)
y - [5] = ![\frac{-2}{5}(x - [-3])\\](https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B5%7D%28x%20-%20%5B-3%5D%29%5C%5C)

Answer: B. 10
-5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. To calculate combinations, we will use the formula nCr = n! / r! ... * (n - r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.
-10 is the total number of all possible combinations for choosing 3 elements at a time from 5 distinct elements without considering the order of elements in statistics & probability surveys or experiments. The number of combinations for sample space 5 CHOOSE 3 can also be written as 5C3 in the format of nCr or nCk.
Step-by-step explanation: Hope this help :D