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kirill [66]
3 years ago
9

Find the prodcut (2b+c)(3b+2c)

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
Use distributive property:
(a + b)(c + d) = ac + ad + bc + cd

(2b+c)(3b+2c)=(2b)(3b)+(2b)(2c)+(c)(3b)+(c)(2c)\\\\=6b^2+4bc+3bc+2c^2=6b^2+7bc+2c^2

Juliette [100K]3 years ago
6 0
Product?  prodcut?

Mult. these 2 binomials together, using the so-called FOIL method:

6b^2 + 4bc + 3bc + 2c^2

simplify:  6b^2 + 7bc + 2c^2 (ans)

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3 years ago
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X intercept f(x)=(x+4)^2
natali 33 [55]

Answer:

<h2>-4</h2>

Step-by-step explanation:

Given the function f(x)=(x+4)², <u>the x intercept occurs at f(x)  = 0,</u> substituting f(x) = 0 into the given equation to get the value of x we have;

0 = (x+4)^{2} \\

Taking the square root of both sides

\sqrt{(x+4})^{2}  = \sqrt{0}\\ x+4 = 0\\

Subtracting 4 from both sides of the equation

x+4-4 = 0-4\\x = -4

Therefore the x intercept of the equation is -4

4 0
2 years ago
Simplify 6 x 10−7 2 x 105 .
mafiozo [28]

Answer:

-49

Step-by-step explanation:

it would be this because first we would have to figure out what 6*10 is that why we know what to distribute . so once we figure it out , which is 70 . We would then subtract 14 from 70 . Since 7 is right next to 2 we would then multiply it to get to 14. Once we get that you should get 56, from there you would subtract 56 to 105 , and get your answer.

7 0
2 years ago
A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat
grigory [225]
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3 0
3 years ago
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At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0
2 years ago
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