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kirill [66]
3 years ago
9

Find the prodcut (2b+c)(3b+2c)

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
Use distributive property:
(a + b)(c + d) = ac + ad + bc + cd

(2b+c)(3b+2c)=(2b)(3b)+(2b)(2c)+(c)(3b)+(c)(2c)\\\\=6b^2+4bc+3bc+2c^2=6b^2+7bc+2c^2

Juliette [100K]3 years ago
6 0
Product?  prodcut?

Mult. these 2 binomials together, using the so-called FOIL method:

6b^2 + 4bc + 3bc + 2c^2

simplify:  6b^2 + 7bc + 2c^2 (ans)

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Lapatulllka [165]
The equation used for this problem is

F = P(1+i)ⁿ
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Substituting the values,

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Answer:

16

Step-by-step explanation:

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After going through this module, you are expected to:
Svetach [21]

Answer:

See below

Step-by-step explanation:

<u>Number of squares:</u>

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The model shows that we are to arrange the factors based on the terms in the square box. The factored form is (5x+2)(2x-1)

<h3>Factorizing quadratic equations</h3>

Factorization is a way of simplify. Given the equation 10x² -x - 2

Factorize

10x² -x - 2

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5x(2x-1)+2(2x-1)

(5x+2)(2x-1)

We are to arrange each term of the factors in the square box

Learn more on factoring here: brainly.com/question/24734894

#SPJ1

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