The probability that both of the students are on Team D is about 5.56%
There are 4 teams, so the first person has a 1/4 chance of being on Team D.
However, for the second person, there are only 6 spots left out of 27 to be on Team D.
To find the combined probability, we need to multiply the two fractions.
1/4 times 6/27 = 1/18 or about 5.56%
Answer:
The diameter is 361 units
Step-by-step explanation:
The formula for circumference of a circle is given by
C = pi *d
We know the circumference = 1133.54 and pi is approximated by 3.14
1133.54 = 3.14 *d
Divide each side by 3.14
1133.54/3.14 = d*3.14/3.14
361=d
The diameter is 361 units
Answer:
B. 23 games.
Step-by-step explanation:
Current balance: $469
Goal balance: $825.50
Profit per game: $15.50
- 825.50 - 469 = 356.50
They only need $365.50 in order to reach the goal.
- 356.50 ÷ 15.50 = 23
They need to sell 23 games, each selling for $15.50, in order to reach their goal balance, of $825.50.
- Therefore, the answer is B.
Answer:

Step-by-step explanation:
Getting all three marbles of green color only happens if every draw is a green marble. On the first marble draw, the urn has 10 marbles in it, out of which 5 are green. So the probability of drawing a green marble on this first draw is 
Then, once this has happened, the second draw also needs to be a green marble. At this point in the urn there are only 9 marbles left, and only 4 of them are green. So the probability of drawing a green marble at this point is 
Afterwards, on the last draw, a green marble also needs to be drawn. At this point there are only 8 marbles left on the urn, and only 3 of them are green. So the probability of drawing a green marble on this last draw is 
Therefore the probability of drawing all three marbles of green color is
