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Sergio039 [100]
3 years ago
9

6a divided by 27/5 is what?

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
I would think <span><span>6a/</span><span><span>‌<span>27/5</span></span>‌</span></span>‌<span>=<span><span>‌<span>10/9</span></span>‌<span>a</span></span></span>
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Find the area of the shaded region. Please help! <br><br> Brainliest to who gets it right !
damaskus [11]
0.367 centimeters squared

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3 years ago
What is the function f(x) = 2(x + 6), find x if f(x) = 22
lord [1]

Answer:

<h3>x = 5</h3>

Step-by-step explanation:

f(x) = 2(x + 6)

f(x) = 22

thereofre we have the equation:

2(x + 6) = 22      <em>use distributive property</em>

2x + 12 = 22     <em>subtract 12 from both sides</em>

2x = 10     <em>divide both sides by 2</em>

x = 5

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3 years ago
How many minutes does the white vacuum need to clean 86.25 square feet?
Dovator [93]

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1.5 hours

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3 years ago
F Andre sold 16 magazine subscriptions this week, would he reach his goal? Explain your reasoning.
Misha Larkins [42]

Answer:

What are some other numbers of magazine subscriptions Andre could have sold and still reached his goal?

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8 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
lbvjy [14]

Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:

f(x)=[1 / (4p)] (x-h)^2+k

where Vertex: V=(h,k)

The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

h=(3+3)/2→h=6/2→h=3

k=(5+1)/2→k=6/2→k=3

Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

f(x)=[ 1 / (-8) ] (x-3)^2 + 3

f(x)= - (1/8) (x-3)^2 + 3

4 0
3 years ago
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