a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10
(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)
a(x-1)+b(x-2)+x+1=9x-10
Now this equation is much simpler!
(a+b)x-a-2b+x+1=9x-10
(a+b)x-a-2b=8x-11
(a+b-8)x-a-2b-11=0
a+b-8=(a+2b-11)/x
I can't solve it 3 variables and 1 equations means infinite answers so yea.
Answer:
The answer is between first option and last option.
Step-by-step explanation:
That my Contributions to this questions
The period will be the length for one cycle of the function.
answer: 10
Answer:
0.12 x (x + 3000) = 4200
equation for her salary last year : last year's salary = (4200 / 0.12) - 3000
$32,000
Step-by-step explanation:
Let x = last year's salary
this year's salary = 3000 + x
this equation can be used to determine how much she saved this year = 0.12 x (x + 3000) = 4200
to find last year's salary, make x the subject of the formula
4200 / 0.12 - 3000 = x
x = $32,000
