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pochemuha
3 years ago
9

How do you work this out

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

Below.

Step-by-step explanation:

To find the number of students in each grade you multiply the marks by the frequency density. The number of students is given by the area under the  rectangles.

So to find the number of students with grade U (< 160)  it is:

120 * 0.2 + 40*0.5

= 24 + 20

= 44.

The number for Grade E

= (200 - 160) * 0.5

= 40 * 0.5

= 20.

The others can be found in the same way.

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Answer:

Step-by-step explanation:

The formulae for simple interest is PxRxT/100 where P is the principal, R the Rate and T the time. P= 1100 R= 4.5 and T= 3. Therefore 1100×4.5×3/100=148.5. Implies the Simple Interest is $148.5

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What makes the number sentence true 5+7=7+
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The answer is 5

Step-by-step explanation:

In the commutative property, the equation goes a+b=b+a

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hope this helps! :D


8 0
3 years ago
Malachy was thinking of a number. Malachy adds 9 then divides by 3 to get an answer of 48. Form an equation with
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Step-by-step explanation:

Let,

  • Number = x

(x+9) \div  3=48

x+9=48\times 3

x+9=144

x=144-9

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Therefore,

The number = 135

6 0
2 years ago
If a chicken lays 16 eggs every 40 days, what is the average number of eggs she lays per day?
Basile [38]

Answer:

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5 0
2 years ago
Read 2 more answers
Please answer all parts of the question and all work shown.
faust18 [17]

Answer:

a. 0.4931

b. 0.2695

Step-by-step explanation:

Given

Let BG represents Boston Globe

NYT represents New York Times

P(BG) = 0.55

P(BG') = 1 - 0.55 = 0.45

P(NYT) = 0.6

P(NYT') = 1 -0.6 = 0.4

Number of headlines = 5

Number of depressed articles = 3 (at most)

a.

Let P(Read) = Probability that he reads the news the first day

P(Read) = P(He reads BG) and P(He reads NYT)

For the professor to read BG, then there must be at most 3 depressing news

i.e P(0) + P(1) + P(2) + P(3)

But P(0) + P(1) + .... + P(5) = 1 (this is the sample space)

So,

P(0) + P(1) + P(2) + P(3) = 1 - P(4) - P(5)

P(4) or P(BG = 4) is given as the binomial below

(BG + BG')^n where n = 5, r = 4

So, P(BG = 4) = C(5,4) * 0.55⁴ * 0.45¹

P(BG = 5). = (BG + BG')^n where n = 5, r = 5

So, P(BG = 5) = C(5,5) * 0.55^5 * 0.45°

P(0) + P(1) + P(2) + P(3)= 1 - P(BG = 4) - P(BG = 5)

P(0) + P(1) + P(2) + P(3) = 1 - C(5,4) * 0.55⁴ * 0.45¹ - C(5,5) * 0.55^5 * 0.45°

P(0) + P(1) + P(2) + P(3) = 0.7438

For the professor to read NYT, then there must be at most 3 depressing news

i.e P(0) + P(1) + P(2) + P(3)

But P(0) + P(1) + .... + P(5) = 1 (this is the sample space)

So,

P(0) + P(1) + P(2) + P(3) = 1 - P(4) - P(5)

P(4) or P(NYT = 4) is given as the binomial below

(NYT+ NYT')^n where n = 5, r = 4

So, P(NYT = 4) = C(5,4) * 0.6⁴ * 0.4¹

P(NYT = 5). = (NYT + NYT')^n where n = 5, r = 5

So, P(NYT = 5) = C(5,5) * 0.6^5 * 0.4°

P(0) + P(1) + P(2) + P(3)= 1 - P(NYT = 4) - P(NYT = 5)

P(0) + P(1) + P(2) + P(3) = 1 - C(5,4) * 0.6⁴ * 0.4¹ - C(5,5) * 0.6^5 * 0.4°

P(0) + P(1) + P(2) + P(3) = 0.6630

P(Read) = P(He reads BG) and P(He reads NYT)

P(Read) = 0.7438 * 0.6630

P(Read) = 0.4931

b.

Given

n = Number of week = 7

P(Read) = 0.4931

R(Read') = 1 - 0.4931 =

He needs to read at least half the time means he reads for 4 days a week

So,

P(Well-informed) = (Read + Read')^n where n = 7, r = 4

P(Well-informed) = C(7,4) * (0.4931)⁴ * (1-0.4931)³ = 0.2695

3 0
2 years ago
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