Answer:
probability of tossing a coin 3 times and getting heads each time is 1/8
Step-by-step explanation:
A coin has 2 sides (heads and tails) therefore you have a 50% chance of getting either heads or tails for each toss. Therefore, the probability of getting heads for 1 toss is 1/2. Now, tossing it 3 times and getting heads each time essentially means you would have to do (1/2)×(1/2)×(1/2) which would give you 1/8 as the probability of tossing a coin 3 times and getting heads each time.
4.
-3/4 - 2/3 ÷ (-4/5)
= -3/4 - [2/3 ÷ (-4/5)]
{switch the numerator and denominator when changing from ÷ to ×, or × to ÷}
= -3/4 - [2/3 × (-5/4)]
{numerator × numerator, and denominator × denominator}
= -3/4 - [-10/12]
= -3/4 + 10/12
= -9/12 + 10/12
= 1/12
5.
-2 2/5 + (-2 4/5) × 4/7
= -2 2/5 - (2 4/5 × 4/7)
= -12/5 - (14/5 × 4/7)
= -12/5 - (56/35)
{Simplify fraction to make denominators same}
= -12/5 - (8/5)
= -20/5
= -4/1
= -4
6.
-(-3/5) - 1 3/7 ÷ (-5/14)
{Negative signs cancelled out, fractions compounded}
= 3/5 - 10/7 ÷ (-5/14)
{Switch numerator and denominator when switch from ÷ to ×}
= 3/5 - [10/7 × (-14/5)]
= 3/5 - [-140/35]
= 3/5 + 20/5
= 23/5
{Simplify fraction}
= 4 3/5
Hope this helps! :) You may ask me for more help if you need
Answer:
1.23 x 10^-7
Step-by-step explanation:
you went back 7 so its negative
1 box =1 foot so you would have to count the boxes away from her
After multiplying each side of the equation by the LCD, the result will be
2(x² - x - 6) = x(x - 6) + 2x(2x + 12)
Then simplify and move all expression the the left of equal sign
2(x² - x - 6) = x(x - 6) + 2x(2x + 12)
2x² - 2x - 12 = x² - 6x + 4x² + 24x
2x² - x² - 4x² -2x + 6x - 24x - 12 = 0
-3x² -20x - 12 = 0
Multiply each side by -1
-3x² -20x - 12 = 0
3x² + 20x + 12 = 0
The answer is third option
