The area of the triangle formed by his path is 34971.98 ft sq to the nearest hundredth.
<h3>What is the Heron's formula?</h3>
The Heron's formula is given as;
√s(s-a)(s-b)(s-c)
where s is half the perimeter of the triangle
WE have been given that horse gallops 200ft, turns and trots 350ft, turns again and travels 410ft to return to the point he started from.
Perimeter of the triangle is given as = 200 + 350 + 410 = 960 ft
Semi perimeter = 960 ft/ 2 = 480 ft
Area = √s(s-a)(s-b)(s-c)
Area = √480 (480 -200)(480 -350)(480 -410)
Area = √480 (280)(130)(70)
Area = √480 (2548000)
Area = 34971.98
The area of the triangle formed by his path is 34971.98 ft sq to the nearest hundredth.
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The complete question is
A horse gallops 200ft, turns and trots 350ft, turns again and travels 410ft to return to the point he started from. What is the area of the triangle formed by his path? round to the nearest hundredth.
Answer:
s=-2
Step-by-step explanation:
Answer:
Option 4 : 
Step-by-step explanation:
<u>See the attached figure:</u>
To find the vertices of the feasible region, we need to graph the constraints, then find the area included by them, then calculate the vertices which is the intersection between each two of them.
As shown, the shaded area represents the solution of the constraints
So, the vertices of the feasible region are:
Answer:
200
Step-by-step explanation:
just add 200 around the whole thing
Please note that dilation does not affect angles. Thus, if an image is dilated the angle remains the same and does not change.
Therefore, even if 
is dilated to 
by a factor of 1.5 (or by any factor for that matter), the linear dimensions of the original triangle will either get stretched or get shrunk by a factor of 1.5 but the angles of the original triangle will not be affected in any case.
Please note that this is true for all two dimensional geometric shapes.
