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Evgesh-ka [11]
3 years ago
10

Find the LCM of 8, 12, and 16. A.48 B.96 C.192 D.1536

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0
A. They all can be multiplied to equal 48
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Subtract (4x+2) from the sum of (6x+1) and (7x+3)
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Answer:11x

Step-by-step explanation:

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3 years ago
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In 1990, California switched from a 6/49 lottery to a 6/53 lottery. Later, the state switched again to a 6/51 lottery. (a) Find
zalisa [80]

Answer:

(a) 9.9321*10^{-11}

(b) 6.0498*10^{-11}

(c) 7.7120^{-11}

(d) 1.6417 times more probable

Step-by-step explanation:

(a) The probability of winning a 6/49 lottery is given by:

P = \frac{1}{49*48*47*46*45*44} =9.9321*10^{-11}

(b) The probability of winning a 6/53 lottery is given by:

P = \frac{1}{53*52*51*50*49*48} =6.0498*10^{-11}

(c) The probability of winning a 6/51 lottery is given by:

P = \frac{1}{51*50*49*48*47*46} =7.7120^{-11}

(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:

r=\frac{9.9321*10^{-11}}{6.0498^{-11}}\\r=1.6417

It is 1.6417 times more probable.

8 0
4 years ago
I had $3.00.
nirvana33 [79]

Answer:

the answer will be $177.

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3 years ago
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M1 Matrix is:
harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

The Inverse of a 2X2 matrix

A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)

can be found using the following:

A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)

Therefore:

M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

Next, we find the product M^{-1}M

M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0
3 years ago
Bill lent some money to his two brothers. He wrote down the amounts so he would not forget. The list shows his younger brother w
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<span>The younger brother owes Bill $12.75, and the older brother does not owe him any money. </span>
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