Suppose that from a group of 30 athletes, 17 compete in a 100-meter race, 8 compete in a

The ratio of girls to boys who participated in the quiz bowl was 7:5. There were 42 girls in the competition. How many boys part

Vlad1618 [11]

7*6=42 girls
5*6=30 boys
7:5=42:30
30 boys participated

4 0

3 years ago

Read 2 more answers

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

3 0

3 years ago

Help me for brainlist

LUCKY_DIMON [66]

Answer:

c

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

3 0

3 years ago

1 +100000 what is the best answer

serg [7]

Answer:

10001 is the answer to your Question

5 0

2 years ago

Which case allows for more than one triangle with the given measures to be constructed?

Anni [7]

<span>A.three sides measuring 9 meters, 5 meters, and 5 meters

--> only one isosceles triangle

B.three sides measuring 6 inches, 3 inches and 9 inches

--> none triangle may be formed because 9 = 3 + 6 and there is a rule (the triangle inequality theorem) that states the length of any side must be less than the sum of the lengths of other two sides.

C.three angles measuring 25°, 25°, and 130°

--> 25 + 25 + 130 = 180 => you can construct many triangles with these angles

D.three angles measuring 55°, 25°, and 125°

--> 55 + 25 + 125 = 205 > 180 => you cannot construct any triangle with theses measures.
</span>

7 0

3 years ago