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777dan777 [17]
3 years ago
9

At a bargain store, Karl bought 3 items that each cost the same amount. Kellie bought 4 items that each cost the same amount, bu

t each was $2.25 less than the items that Karl bought. Both Karl and Kellie paid the same amount of money. what was the individual cost of each person's items?
Mathematics
1 answer:
Licemer1 [7]3 years ago
4 0

Hello...

Karl bought 3 items that all share the same price.

p = price

Then Kellie bought 4 items that each cost the same amount, but each was $2.25 less than the items that Karl bought. So, we will call this 4(p - 2.55).

We put parentheses around the p and 2.55 because Kellie's items all are $2.55 less than Karl's.

Solution:

3p = 4(p - 2.55)

Distributive Property:

3x = 4p - 10.2

-p = -10.2

Find the opposite of 4p.

p = 10.2

3(10.2) = 4(10.2 - 2.55)

36=36.

Karl's price - $10.2

Question - $2.55

$10.2 - $2.55 = $7.65

Kellie's items - $7.65.

Individual Prices:

Karl - 10.2 / 3 = 3.4

Kellie - 7.65 / 4 = 1.9125 = 1.91

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Answer:

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b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

We dont know the true proportion, so we use \pi = 0.5, which is when we are are going to need the largest sample size.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2

n = 2401

The minimum sample size is 2401.

4 0
3 years ago
If angela swims 1700 meters in 40 minutes what is her unit ratio?
Licemer1 [7]
 you would divide 1700 by 40

1700/40= 42.5

there for the unit ratio would be 42.5 meters per minute
7 0
3 years ago
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Please help it’s for geometry
vredina [299]

Answer:

x=25

Step-by-step explanation:

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3 0
3 years ago
Omg, I need help! A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6
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Answer:

Average size of the lots = ⅓ acre

Step-by-step explanation:

The question incomplete without specifying what we are to determine.

Question:A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X's. Organize the information in a line plot. What is the average size of the lots? _________ acre

Help anyone?

Solution:

We are asked to organize the information in a line plot. See attachment for the line plot.

Given: 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X'sIn no particular order, the sizes of the lots are:1/6, 1/6, 1/6, 1/6, 1/6, 1/6, 1/3, 1/3, 1/3, 1/2, 1/2, 1/2, 1/2, 1/2 and 1/2 acre.

Let's count the number of lot for each size given.

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= the lot × number of times it occurs

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The total number of lots given = 15

Average size of the lots = 5/15 = 1/3

Average size of the lots = ⅓ acre

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3 years ago
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