I think they have the answer to this online regents answer and a non regents answer
Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Answer:
wym i canr see the examples
Explanation:
Answer:
D
Explanation:
A stomata is responsible for opening up, to allow gas exchange which is needed for photosynthesis .
Answer:
46 chromosomes
Explanation:
<em>I. G1 phase (Gap 1) - Cellular contents excluding the chromosomes, are duplicated. II. S phase (DNA Synthesis) - Each of the 46 chromosomes is duplicated by the cell.</em>