Rational number because for a number to be irrational it needs to have a decimal or be smaller than 1
Answer:
![h = \dfrac{A - 9}{6}](https://tex.z-dn.net/?f=%20h%20%3D%20%5Cdfrac%7BA%20-%209%7D%7B6%7D%20)
Step-by-step explanation:
A=b^2+2bh
b = 3
A = 3^2 + 2(3)h
A = 9 + 6h
6h = A - 9
![h = \dfrac{A - 9}{6}](https://tex.z-dn.net/?f=%20h%20%3D%20%5Cdfrac%7BA%20-%209%7D%7B6%7D%20)
Answer:
Option A. √(x + 1)
Step-by-step explanation:
Data obtained from the question include:
f(x) = √(x² – 1)
g(x) = √(x – 1)
(f/g) (x) =..?
(x² – 1) => difference of two square
(x² – 1) => (x – 1)(x + 1)
f(x) = √(x² – 1)
f(x) = √(x – 1)(x + 1)
(f/g) (x) = f(x) /g(x)
f(x) = √(x – 1)(x + 1)
g(x) = √(x – 1)
(f/g) (x) = √(x – 1)(x + 1) / √(x – 1)
(f/g) (x) = √[(x – 1)(x + 1) / (x – 1)]
(f/g) (x) = √(x + 1)
Answer:
It would be -7
Step-by-step explanation:
The 12 is negative, so instead of adding, you would subtract 5.