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Eddi Din [679]
3 years ago
9

What is the coefficient of x in 2x + 5 = 8​

Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer:

2

General Formulas and Concepts:

<u>Algebra I</u>

  • Leading Coefficients vs Constants

Step-by-step explanation:

The leading coefficient will always be the number multiplied to the highest degree variable.

Our highest degree term is 2x. Our leading coefficient would then be 2.

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Help please bad please ​
Sergio [31]

Answer:

\displaystyle A .20

Step-by-step explanation:

<u>By </u><u>tangent</u><u> </u><u>theorem</u><u> </u>we acquire:

\displaystyle  x + 10 = 9 + 21

simplify addition:

\displaystyle  x + 10 = 30

cancel 10 from both sides:

\displaystyle  x = 20

hence,

our answer is A

4 0
2 years ago
Choose the right answer.
Pavel [41]

Step-by-step explanation: last year

3 0
3 years ago
Read 2 more answers
(Im sure this is a easy answer but im just double checking)
IgorC [24]
This answer seems to be C
5 0
3 years ago
Find thhe remainder when 7^203 is divided by 4
Aleksandr [31]
Using the square-and-multiply approach, we have

7^{203}=7\times(7^{101})^2
7^{101}=7\times(7^{50})^2
7^{50}=(7^{25})^2
7^{25}=7\times(7^{12})^2
7^{12}=(7^6)^2
7^6=(7^3)^2
7^3=7\times7^2

and so, using the property that, if a_1\equiv b_1\mod n and a_2\equiv b_2\mod n, then a_1a_2\equiv b_1b_2\mod n, we get

7\equiv3\mod4
7^2\equiv9\equiv1\mod4
7^3\equiv7\times1\equiv7\equiv3\mod4
7^6\equiv9\equiv1\mod4
7^{12}\equiv1\mod4
7^{25}\equiv7\times1\equiv7\equiv3\mod4
7^{50}\equiv9\equiv1\mod4
7^{101}\equiv7\times1\equiv7\equiv3\mod4
7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4
4 0
3 years ago
Write "The total of a number t and 11" as an algebraic expression.
timofeeve [1]
T+11 because total would mean add them
5 0
3 years ago
Read 2 more answers
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