For
ax^2+bx+c=
and a=1
b/2 squared=c makes a perfect square
b=16
16/2=8
8^2=64
the value of c should be 64
factored form
(x+8)^2
Im guessing 3 i really dont know.. i dont understand what it means by 4 channels.
The absolute value of -8 is 8
here’s a trick the absolute value of a positive is the same number of its negative it’s the same number but positive
hope it helps
Answer:
![\boxed{ \tt{x = 4}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Ctt%7Bx%20%3D%204%7D%7D)
Step-by-step explanation:
![\frac{3}{x} = \frac{6}{8} \\ 6x = 24 \\ x = 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7Bx%7D%20%20%3D%20%20%5Cfrac%7B6%7D%7B8%7D%20%20%5C%5C%206x%20%3D%2024%20%5C%5C%20x%20%3D%204)
Answer:
See below. <u><em>I assume that (x) = 8x2 - 7x + 3 is really (x) = 8x^2 - 7x + 3</em></u>
Step-by-step explanation:
Substitute the value of x given in f(x) into the equation f(x) = 8x^2 - 7x + 3
For example, f(0) would be f(0) = 8(0)^2 - 7(0) + 3. f(0) = 3
f(-2) would be f(-2) = 8(-2)^2 - 7(-2) + 3.
= 8*4 + 14 +3
= 32 + 17 therefore f(-2) = 49
<u>x</u> <u>f(x)</u>
-2 49
-1 18
0 3
1 4
2 21