144 cannot be a factor of 72 since it is bigger than 72
We need to find a common denominator for the bottom half of the fraction. To do so, we will first factor
![x^2-3x-4](https://tex.z-dn.net/?f=x%5E2-3x-4)
.
![x^2-3x-4 = (x+1)(x-4)](https://tex.z-dn.net/?f=x%5E2-3x-4%20%3D%20%28x%2B1%29%28x-4%29)
Notice that both denominators have a x+1 in common. To get the common denominator, we need to multiple the
![\frac{5}{x+1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7Bx%2B1%7D%20)
by its missing piece, (x-4)
![\frac{5(x-4)}{(x+1)(x-4)} - \frac{x+4}{(x+1)(x-4)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%28x-4%29%7D%7B%28x%2B1%29%28x-4%29%7D%20-%20%5Cfrac%7Bx%2B4%7D%7B%28x%2B1%29%28x-4%29%7D%20)
Combine:
![\frac{4(x-6)}{(x+1)(x-4)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%28x-6%29%7D%7B%28x%2B1%29%28x-4%29%7D%20)
When dividing two fractions, we can flip the second one and multiply.
![\frac{1}{3(x+1)(x-1)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%28x%2B1%29%28x-1%29%7D)
×
![\frac{(x+1)(x-4)}{4(x-6)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x%2B1%29%28x-4%29%7D%7B4%28x-6%29%7D%20)
There is an (x+1) in the numerator and denominator that cancel.
Answer:
Answer:
129.25
Step-by-step explanation:
Area of the rectangle
Area = L * W
L = 10
W = 9
Area = 9 * 10 = 90
Area of the1/2 circle
Area of a whole circle = pi * r^2
Area of a 1/2 circle = pi * r^2 /2
d = 10
r = d/2
r = 10/2
r = 5
Area of the 1/2 circle = 3.14 * 5^2 /2 = <u> 39.25</u>
Total 129.25
This ordered pair is not a solution for the given equations. We can tell this by plugging in to each of them and seeing that it does not provide a true statement for both. It does work for the first, but is not an intersection due to it not working for each.
4x - 3y = 30
4(6) - 3(-2) = 30
24 + 6 = 30 (TRUE)
3x + 2y = 22
3(6) + 2(-2) = 22
18 - 4 = 22
16 =/= 22 (FALSE)