Answer:
32q5
Step-by-step explanation:
2x2x2x2x2= 32 qxqxqxqxq=q5
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Answer: T = 2π√(I/mgD)
Step-by-step explanation:
where:
m is the mass of the pendulum;
I is the moment of inertia of the mass; and
D is the distance from the center of mass to the point of suspension.
Determine the length of the pendulum. For example, it can be equal to 2 m.
Decide a value for the acceleration of gravity. We will use the Earthly figure of 9.80665 m/s², but feel free to check how the pendulum would behave on other planets.
Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s.
Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz.
You can also let this simple pendulum calculator perform all calculations for you!
8+(9t+4)
remove ( )
since there's a + in front of the ( ) the value will not change
8+9t+4
combine like terms
9t+12
Hope this helps
