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Natasha2012 [34]
3 years ago
13

If you wanted to increase the rate of photosynthesis in a plant, you would develop a plant with which of the following character

istics? a strong, thick stalk bright flowers to attract bees many, broad leaves short, narrow leaves
Biology
2 answers:
WARRIOR [948]3 years ago
8 0
Many broad leaves, which allows gathering more light. 
Mila [183]3 years ago
3 0

In order to increase the rate of photosynthesis in a plant, a plant should be developed with many broad leaves. The broad leaves will have increased surface area and more chlorophyll. The increased number of the leaves in the plant will also contribute to the overall increased rate of the photosynthesis.

A strong and thick stalk will support the plant but will have no effect on the rate of photosynthesis. Narrow leaves will decrease the photosynthesis rate. Bright flowers will aid in pollination via the honeybees but not increase the photosynthesis rate.

Hence, the correct answer is 'many broad leaves'.

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The right answer is C. Breaking the bonds in a monosaccharide.

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4 0
2 years ago
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In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive plant having fasciated fruit an
Pani-rosa [81]

Answer:

Recombination frequency, P = 0.23.

If the recombination frequency is < 50%, genes are linked. A RF of 23% tells us that these two genes are in the same chromosome, close enough to be linked.

  • 1% of recombinations = 1 map unit
  • 23% = 23 map units

The genes for stem color and fruit type seem to be in the same chromosome, linked and 23 MP apart.

Explanation:        

In the present example, the genes for stem color and fruit type seem to be linked.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.  

In this way, we might verify which are the recombinant gametes produced by the di-hybrid, and we will be able to recognize them by looking at the phenotypes with <u>lower frequencies in the progeny</u><u>.</u>    

The following distribution of offspring is observed:

  • normal fruit, purple stems 38.5%
  • fasciated fruit green stems 38.5%
  • normal fruit, green stems 11.5%
  • fasciated fruit, purple stems 11.5%

38.5% + 38.5% + 11.5% + 11.5% = 100%

N (total number of individuals in the progeny) = 100

  • number of individuals with normal fruit, purple stems 38.5
  • number of individuals with fasciated fruit green stems 38.5
  • number of individuals with normal fruit, green stems 11.5
  • number of individuals with fasciated fruit, purple stems 11.5

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU).

P = Recombinant number / Total of individuals.

P = 11.5 + 11.5 / 100

P = 0.23  

We need to know that 1% of recombinations = 1 map unit = 1cm. Also, the maximum recombination frequency is always 50%.  This means that if the recombination frequency is < 50%, genes are linked. A RF of 23% tells us that these two genes are in the same chromosome, close enough to be linked. FR 23% = 23 UM.  

 

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