Answer:
x = 3 or x = 2 or x = -6
Step-by-step explanation:
Solve for x:
(x - 3) (x^2 + 4 x - 12) = 0
Split into two equations:
x - 3 = 0 or x^2 + 4 x - 12 = 0
Add 3 to both sides:
x = 3 or x^2 + 4 x - 12 = 0
The left hand side factors into a product with two terms:
x = 3 or (x - 2) (x + 6) = 0
Split into two equations:
x = 3 or x - 2 = 0 or x + 6 = 0
Add 2 to both sides:
x = 3 or x = 2 or x + 6 = 0
Subtract 6 from both sides:
Answer: x = 3 or x = 2 or x = -6
Answer:
4 need to join the club to remain same to grade 8th
Is it −26−(6)^2? If so
−26−(6)^2
= -26 - 36
= - 62
If −26−(6)2 (means 6 times 2) then
= -26 - 12
= -38
Answer:
Jacob served 16 quarts of juice.
Step-by-step explanation:
Answer:


Step-by-step explanation:
Given the matrices


Calculating AB:

Multiply the rows of the first matrix by the columns of the second matrix


Hence,

Therefore,

